The following aqueous solutions were tested with a light bulb conductivity apparatus, as shown in Figure 4.3. What result—dark, dim, or bright—do you expect from each? (a) 0.10 M hydrofluoric acid (b) 0.10 M sodium chloride (c) 0.10 M glucose (C6H12O6)

Video transcript

Hey everyone, we're told that each of the following acquis solutions was tested using the conductivity apparatus shown below, predict whether the light bulbs in each would result in bright, dim or dark. So let's go ahead and look at our options here. So for a we have 0.25 molar of sucrose. And as we know, sucrose is a sugar, which means it is a non electrolyte. And because it is a non electrolyte, that means it does not produce ions, so it will not conduct electricity. So our light bulb here will be dark. Now let's go ahead and look at B. So for B we have 0.25 moller of phosphoric acid. As we know, phosphoric acid is a week acid and because it is a weak acid, that means it is a weak electrolyte. So this will partially I nice and because it will partially ionized, it will conduct electricity. So this light bulb will actually be dim. Now let's go ahead and look at C. So for C we have 0.25 molar potassium nitrate. As we know potassium nitrate is a soluble salt. So this is a strong electrolyte which means it will completely disassociate. So it will also conduct electricity. Now our light bulb for our 0.25 Molar potassium nitrate will be bright and these are going to be our final answers. Now, I hope that made sense. And let us know if you have any questions