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Ch.4 - Reactions in Aqueous Solution

Chapter 4, Problem 63

A galvanic cell is constructed from a Zn/Zn2+ half-cell (anode) and a Cl2/Cl- half-cell (cathode). (b) Write balanced equations for the electrode and overall cell reactions.

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Welcome back everyone for a galvanic cell. The note half cell is nickel, nickel two plus. And the cathode half cell is flooring, fluoride an eye on what are the balanced electrode equations and balanced overall cell reaction. So for our electrode equations, we want to come up with a equation for our an ode cell. And then for our cathode cell. So beginning with our anodes cell, according to the prompt that consists of nickel and our nickel two plus carry on. So we would begin with solid nickel, which forms are nickel two plus catalon. And we just need to make sure that this is balanced. So we have balanced atoms but we have a net charge of plus two on the product side. So to balance out our charges, we're going to add two electrons to the product side to cancel out that plus two charge that we have an overall neutral charge on our entire reaction. And now going to our cathode half cell according to the prompt that consists of flooring and our fluoride an ion. So we have our flooring gas which is F two gas and it produces are f minus an ion Where we need to bounce out the atoms here. So we're going to recognize on the reactive side, we have two moles of flooring. So we need two moles of flooring on the product side. And we'll do that by placing a coefficient of two in front of our fluoride an ion. And now we need to bounce out the charges by recognizing that on the product side with that coefficient of two added, we now have a net charge of -2 on the product side. And so to Mend that we're going to expand our react inside and gain a net charge of -2 by adding two electrons as a reactant here. And so now we can come up with our overall cell reaction by making sure that our electrons are balanced in both reactions, which they are because they both are two electrons. And so we can add these two reactions together to come up with our overall reaction. So we'll have Nichols, solid producing nickel two plus candy on Plus our two electrons and adding these together. We have our overall cell reaction where we can cancel out the two electrons on the product side here and on the reactant side here and what we're left with is solid nickel with our flooring gas which produces our products nickel to plus And two moles of our fluoride an ion. And so for our final answers, we've determined our electorate equations being are an ode equation and our catholic equation here and then our overall cell reaction is also highlighted here in yellow for our third final answer. So I hope that everything I reviewed was clear. If you have any questions, please leave them down below and I'll see everyone in the next practice video