Skip to main content
Ch.4 - Reactions in Aqueous Solution
Chapter 4, Problem 54b

How many grams of solute would you use to prepare the following solutions? (b) 1.50 L of 0.250 M glucose (C6H12O6)

Verified Solution

Video duration:
2m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Molarity (M)

Molarity is a measure of concentration defined as the number of moles of solute per liter of solution. It is expressed in moles per liter (mol/L). Understanding molarity is crucial for calculating how much solute is needed to achieve a desired concentration in a given volume of solution.
Recommended video:
Guided course
00:53
Molarity Concept

Moles of Solute

A mole is a unit that quantifies the amount of substance. One mole of any substance contains Avogadro's number of entities (approximately 6.022 x 10^23). To find the number of moles needed for a solution, you multiply the molarity by the volume of the solution in liters.
Recommended video:
Guided course
00:27
Mole Fraction Formula

Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). It is essential for converting between moles and grams. For glucose (C6H12O6), the molar mass is approximately 180.18 g/mol, which is used to calculate the mass of solute required for the solution.
Recommended video:
Guided course
02:11
Molar Mass Concept