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Ch.23 - Organic and Biological Chemistry

Chapter 23, Problem 23.31

Convert the following models into a condensed structures and line drawings.

(a)

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Welcome back, everyone convert the given 3D model into condensed and line angle formulas. For this problem. We have to recall that the color coding or hygiene atoms would be white. So all of those white atoms, they are hygienes and the gray ones, they are carbon atoms. So we are ready to begin because those are the only two colors present in the structure. And what we can do is just begin with our carbon chain. We have carbons 1234 567 and eight. So we noticed that we have our six member chain, that's our longest continuous carbon chain. So we can just draw one, 2345 in six carbons. And we noticed that carbon number five is bonded to carbon number seven and carbon number four is bonded to carbon number eight. So we have our carbon chain and now we are ready to add the missing hygen. Carbon. Number one has three Hygen car number two has two hydros. Carbon number three has two hydrogens. Carbon number four has a one hydrogen and also it is bonded to carbon number eight which contains three hys one C three, moving on to carbon. Number five, carbon, number five has one hygen only and then it is bonded to a methyl group, right. Carbon number seven contains three hygen followed by carbon number six. At the end of the chain, we have three hygen bondt set. So we want to convert this into a condensed structure. And that means not showing any bonds at all. We can begin from left to right. And we can say that first of all, we have siege three followed by CH two, right. So let's write down CH three, followed by C two, another CH two followed by CH. And this is where we have to be careful. Carbon number four contains branching. It has its own substituent, right. And that means we want to use branches to indicate that the previously written carbon in our condensed formula has its substituent which is CH three. Now, from here, we have CH and once again, we're adding parentis to indicate the presence of a substituent that is a methyl substituent. And finally, we are just indicating that final methyl group C three. That's our condensed structure. Condensed structures essentially look like a text line. It doesn't show any bonds, it only shows carbons and hydrogens as well as parent C to indicate separate substi. And now for the line angle structure, we can just consider our parent chain, our parent chain consists of 123456 carbon atoms. So what we can do is just draw a six member chain using lines, every vertex and corner has an implicit carbon. So we have one, 23, four, five and six carbon atoms. And we know that at the end of the chain, we have two metal substituents. So carbon number two, if we count from right to left has a methyl substituent, we're going to draw an additional line in carbon. Number three. If we count from right to left has a methyl substituent. Now we can check if we are correct. We have 12, let's label them one carbon, two carbons, 345 and six. Well done. And now at the end of the chain, we have our metal group. So CH three and under CH three, that's our align angle structure. Well, then we have our final answers. Thank you for watching.