Write the formula for each of the following compounds.

(c) Tris(ethylenediamine)platinum(IV) sulfate

(d) Triamminetrithiocyanatorhodium(III)

Video transcript

Hello everyone. Today we have the following problem. Give the chemical formula for the compound below potassium hex ayano fate three. So first let's break the name down. We have potassium, which indicates that we have potassium ions in the compound. We didn't have hex ayano, which indicates that we have six because hea means six. And cyano refers to the cyanide li lien. So there are six of these cyano Liggins and then we have fair 83, which just signifies that we have a an iron with an oxidation number of positive three. So let's now consider our charges. Our iron has a positive three charge and our cyano group has a negative six charge because cyanide has a negative one charge, but we have six of them. So it's a negative six charge. We will ignore the potassium charge for now. And we see that this equals a negative three charge. So we need to figure out how many potassiums we need to balance our negative three charge since each potassium ion has a positive one charge, if we have three of them, that balances our complex ion charge out. So we have potassium followed by our complex ion brackets of the iron, we have the hex acient no group. And if we look at our answer choices, we can see that answer choice a best reflects this. And with that, we've answered the question overall, I hope this helped until next time.