Give the products of the following nuclear reactions. (b)

Video transcript

Welcome back everyone in this example. We have four new elements synthesized and formally accepted on november 2016. These elements were synthesized and discovered by bombarding target elements with heavy ions using high energy particle accelerators were told that the nuclear reaction below involves a heavy ion bombardment and we need to complete and give the balanced reaction. So this term thus should not be in our prompt. Going to are given reaction here. We have americium 2 43 which we can recall is located in the f block of our periodic table and correspond to the atomic number reacting with our calcium 48 which we can find in Group two A of our periodic table with atomic number 20. As products we will produce three moles of our beta particle being our neutron with the atomic number zero and mass number one. And we are also producing an unknown new glide which we will call X. Where we need to determine its unknown mass number A and it's unknown atomic number Z. So A we recall is our mass number and ZB recalls a symbol to represent atomic number. So we're going to need to set up two expressions to solve for A and Z. So let's begin with solving for a Beginning with a. We're going to plug in our notes, we know that from americium we have a mass number of 243 reacting with our second mass number of 48 from calcium set equal to our product side where we have three moles of our mass number of our neutron being one. So we're multiplying that value by our mass number one. And we're adding to this our unknown mass number a two sulfur A. So what we would simplify too is to 91 equal to three times one. Which would give us three. So three plus A. And so simplifying for a. We would say that are unknown mass number is equal to 288. Moving forward to solve for our unknown atomic number Z. We're going to plug in our knowns for an expression. We know that our atomic number for americium given in the prompt is added to our second reactant. Atomic number being 20 for calcium set equal to our product side where we have three times our atomic number of our beta neutron particle being zero Added to our second product, which has an unknown atomic number of Z which we are solving for. So simplifying this, we would have 115 equal to Z. And because we would look to our periodic table to determine what this atomic number means, we would see that this corresponds to the atom muscovy um represented by M under case C. And if you have an extended periodic table you would be able to see the atom muscovy um with the atomic number 115. So to write out our complete balanced nuclear equation, we're going to have americium 2 atomic number 95 with americium reacting with calcium 48 its atomic number 20 producing three beta emissions. Where we have our neutron particle corresponding to its atomic number of zero and mass number of one and the adam Muscovy um as our product new glide with the atomic number 115 and the mass number 288. And so our final answer is going to be this entire balanced nuclear reaction. As our final answer. To complete this prompt. I hope everything I reviewed was clear. If you have any questions, leave them down below and I will see everyone in the next practice video.