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Ch.20 - Nuclear Chemistry

Chapter 20, Problem 20.31d

Complete and balance the following nuclear equations.

(d) <ISOTOPE CHEM REACTION>

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Welcome back, everyone complete the nuclear equation shown below. Our given equation contains potassium 49 and it reacts sweat and electron. Let's recall that whenever we want to complete a nuclear equation, we need to introduce an unknown species. A let's call it a right. We will determine that symbol and let's introduce its atomic mass M and it's atomic number C. What we want to do is, first of all identify MNZ, we are going to apply the law of mass conservation and charge conservation. So M should be a sum of the individual atomic weight. One of them is coming from potassium which gives us 42 and the other one is coming from the electron which is zero and we're going to apply the law of charge conservation. Looking at the subscripts, we have 19 on the bottom for potassium and we want to add negative one coming from the electron and this should be equal to Z on the product side. Now, what can we see? Well, M or the atomic mass would be 42 atomic mass units and Z would be 19 minus one. That's 18. So our species has an atomic mass of 42 and an atomic number of 18, if we consider this atomic number, and we can notice that this is organ, which is our unknown species. A and therefore, we can now write a complete equation. We have 4219 K, potassium combines with an electron to produce our species has M of 42 Z of and its symbol is argo A R. Well done. That's our final answer.
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