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Ch.19 - Electrochemistry

Chapter 19, Problem 64

Write balanced equations for the electrode and overall cell reactions in the following galvanic cells. Sketch each cell, labeling the anode and cathode and showing the direction of electron and ion flow. (a) .

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Hello. And this problem for the given cell notation, we are asked to write an overall cell reaction. Were asked to draw the cell diagram label, which electrode is the anodes and cathodes draw arrows to show the direction in which the ions and the electrons flow. So let's first begin by looking at our cell notation. So on the left hand side we have the an ode separated then from the cathode by double vertical line which represents the salt bridge. On the right hand side. These are cathode and we have single vertical lines that separate phases. So solid from Aquarius and Aquarius from a solid writing. Then our reaction that occurs at the anodes. It follows the cell notation and moving from left to right. So we have manganese metal being oxidized to form manganese two plus. And at the cathode again it proceeds as shown from left to right. So we have iron too being reduced to form iron metal. And then we can combine these two reactions. To get our overall reaction, we see that we have two electrons are being lost and two that are being gained. So those will cancel what's left then is our overall reaction. So manganese reacting with iron to for manganese too and iron metal. So this is our overall cell reaction. They were then asked to draw cell diagram. So just as our cell notation set up on the left hand side is the anodes. On the right hand side is the cathode in the annals compartment. Then our electrode is manganese and in the cathode compartment, our electrode is iron. These two electrodes are attached to another through a wire which passes through a volt meter. Since this is a voltaic cell, the manganese and electrode is the negative pole and the cathode, iron electrode is the positive pole. These two compartments are connected by a salt bridge and if we assume that it contains potassium chloride, then the potassium ions. Lines are going to move towards the cathode compartment and are an eines corridor. Lines are going to move towards the an ode compartment at the piano. Then we are oxidizing manganese for manganese. Two plus so those ions are going to move away from the electrode. And in the case of the cathode, the iron too is being reduced from iron metal, the iron two plus ions moving towards the cathode. And then we have our electrons. So the electrons are being generated at the an ode and they move towards the cathode so they're moving from left to right. So this shows then our overall cell reaction and to sell diagram indicating the analytic cathode compartment and then the movement of electrons and ions. Thanks for watching. Hope this helps