Ideal gases A (red spheres) and B (blue spheres) occupy two separate bulbs. The contents of both bulbs constitute the initial state of an isolated system. Consider the process that occurs when the stopcock is opened.

(b) What are the signs ( + , - , or 0) of ∆H, ∆S, and ∆G for this process? Explain.

Video transcript

Hello everyone today. We have the following problem. Three vessels were occupied by ideal gasses, X. For the gray spheres, Y. For the yellow spheres and Z for the green spheres separately. The contents of the vessels represent the original state of an isolated system. When the stop cocks are open, determine the signs positive, negative and zero of our changing our change in entropy and are changing gibbs free energy for the process that occurs. So when the stop clocks are opened, these ideal gasses are going to mix together and so for the mixing of ideal gasses, there is essentially no heat that is gained or lost during the process and therefore our change in our entropy is going to equal zero. Furthermore, when we mix these ideal gasses, it's going to increase the disorder in the system. Therefore our changing our entropy is going to be greater than zero or it's going to have a positive sign. And lastly mixing these ideal gasses is a spontaneous process and therefore our change in our gifts. Free energy is going to be less than zero or have a negative sign. And so with that we have our answer overall, I hope this helped. And until next time