Use the following solubility data to calculate a value of Ksp for each compound. (d) Zn(CN)2; 4.95 x 10^-4 g/L

Video transcript

Hello everyone today. We have the following problem. Barium acetate has a solid ability of 600 g per liter determine the value of K. S. P. For barium acetate. So the first thing I wanna do is we want to recall the molecular weight for better master if we take The individual weights of our barium, our carbons are hydrogen and our oxygen's we're going to get 255.415 g per mole. Next we can determine the concentration of our bedroom sulfate. And so how are we going to do that? Well we're going to take our cell ability which was grams per liter. We're going to divide that by our molar mass which was 255.415 g per mole. And when our units cancel we're going to get 2.35 most per liter or 2.35 Moller. Next we're going to create an ice chart for the reaction. So we're going to have our barium acid tape as a solid and it's going to dissociate into barium two plus acquis ions as well as to acetate ions. We have our initial change in equilibrium rose solid are not included in this table. So we're not going to include anything for barium acetate. The initial concentrations for our barium and our acetate er zero. And then the change is going to be represented by X plus X. For barium because we're gaining these products and then plus two X. For acetate. Because we have two of them. Our equilibrium is going to be the I plus the C. Giving us X and two X respectively. For their concentrations. Next we need to construct our k sp expression and K s p k s p expressions include products over the reactant. However, we only have two products that are the acquis forms solid tonight included. So we just have our barium and our acetate. We solve for our polarity here earlier and this is actually going to be equal to X. Therefore, if this is equal to X, which is the concentration of our berry, um Two x is going to be two times our 2.35, giving us 4.7 moller. So from our k sp we're gonna multiply their concentrations, We have 2.35 Times our 4.7 moller. And that is going to be squared. The square is going to come from this coefficient here. And when we multiply these two numbers, we're gonna get a K S. P value of 51.9 and now we have solved the problem overall, I hope this helped. And until next time