If the following solutions are mixed, is the resulting solution acidic, basic, or neutral? (a) 50.0 mL of 0.100 M HBr and 30.0 mL of 0.200 M KOH

Video transcript

Hello. Everyone send this video dealing with this mixture right over here and we're being asked if it's going to be acidic, basic or neutral. So the first thing I'm gonna do is write out this reaction. So we're given the starting reagents already. So we have H. C. L. And N. A. O. H. So here we can see that there's a double displacing reaction going on. So what this means is that we're going to basically switch partners between the cat ion and ion. So the first product that it will form is an A. C. L. So this is salt. This is a solid as well as H. 20. Which is in a liquid state. So we use this reaction then this direction right over here to do some dimensional analysis. So we're starting off with 25 ml of hcl. Of course hcl is going to be our acid. So here we're gonna convert our male leaders and to leaders. So for every 1000 ml there's one leader and then with our leader we can now go ahead and use our malaria t. Of hcl as a conversion factor. So for every one leader of hcl We have 0.150 moles of hcl. So we'll see if we multiply everything that our knowledge of hcl council leaders of hcl council and they'll just give us the moles of hcl. So putting all my numerical values into calculator. I would get the value of 0.375 moles of hcl now doing the same exact thing with the given amount of Noh starbase. So this time we have 50 mL starting with for N A O H. Again I'm gonna convert female leaders into leaders. So same exact conversion factor Now we'll go ahead and use the morality of R N A O H. So for every one liter of N A O H we have 0.175 moles of Noh. So we see here now that are units of millions will cancel. Units of leaders will cancel. Alright, so I'm putting all my values into the calculator. I would get the value of 0.00875 units being moles of RNAH. So since we have a 1-1 ratio between our two star materials, we can just use the values that would just calculate for So we can compare. Then this 0.00375 vs are 0.00875. We see that the value on the right is going to be greater. And as I recall that the value on the left right over here, that's of our acid are hcl and then to the right is our value of the base. And because the value of our bases greater doesn't means that the overall solution is going to be basic. So you say that therefore the solution is basic. So then this right here is going to be my final answer for this problem