Is the solubility of Fe(OH)3 increased, decreased, or unchanged on addition of each of the following substances? Write a balanced net ionic equation for each dissolution reaction. (See Appendix C.6 for formulas of complex ions.) (b) NaOH(aq)

Video transcript

Welcome back everyone. When potassium hydroxide is added to the solution will assault ability of nickel to hydroxide increase, decrease or remain the same give the balanced net ionic equation for the dissolution process and were given a hint which says to refer to the complex ions formation. So beginning with our potassium hydroxide, recall that it's one of our memorized strong bases and will fully dissociate to form its ion products as our potassium or sorry, our potassium plus one canyon And our hydroxide 1 -5. Now focusing on our solid nickel to hydroxide which is an ionic compounds consisting of our metal nickel and our poly atomic an ion hydroxide. We will this salt will disassociate an equilibrium to form its ion products as our nickel two plus catty on and hydroxide. Now, we need to make sure that this is balanced. So we'll place a coefficient of two in front of our hydroxide product. And notice that these two ions do not react with one another. And so therefore, they will not form a complex. However, between our salt and our base potassium hydroxide, we should notice that we have a common ion which is our hydroxide an ion. And notice that hydroxide are common ion is present on the product for both of these reactions. Meaning that equilibrium for our dissolution of nickel to hydroxide is going to shift towards the left. And because equilibrium shifts towards the left, that means our concentration of our ions nickel two plus and hydroxide are going to decrease. And so this will ultimately also decreased the cell ability of our nickel to hydroxide. So what we've outlined our, our final answers where we have our net ionic equation for our dissolution of nickel to hydroxide. So that would be this entire equation that we've outlined with the coefficient of two in front of hydroxide. And we've also confirmed that because equilibrium shifts to the left due to the presence of hydroxide as our common ion product, our concentration of our ion products will decrease. And therefore, because equilibrium shifts towards our solid nickel to hydroxide, the scalability of this salt will decrease. And so what's highlighted in yellow are our two final answers corresponding to choice. C in the multiple choice. I hope everything I reviewed was clear. If you have any questions, please leave them down below. And I'll see everyone in the next practice video.