A 0.0100 mol sample of solid Cd(OH)2 (Ksp = 5.3 x 10^-15) in 100.0 mL of water is titrated with 0.100 M HNO3. (c) How many milliliters of 0.100 M HNO3 must be added to completely neutralize the Cd(OH)2?

Video transcript

Hello everyone today. We have the following problem a 0.1 50 molar hydrochloric acid solution was used to titrate a 0.1 to zero mol sample of nickel hydroxide with the following que sp and 150 mL of water, calculate the volume in milliliters of the hydrochloric acid solution required to neutralize the nickel hydroxide completely. So first you wanna draw what our reaction would look like. So we would have our nickel hydroxide and it would dissolve in a reversible reaction to nickel 2-plus ions as well as to hydroxide ions, nickel hydroxide due to it having a lo que sp also has a low salt ability. So nickel hydroxide has a low sol you ability. However, the h plus ions from hydrochloric acid will react with hydroxide. So what does this mean? The overall reaction is going to be as follows. We're going to have nickel hydroxide plus to hydrochloric acid ions or molecules to react to form our nickel chloride And two water molecules. So if you look at our ratio here, we see that we have one mole of our nickel hydroxide for every two moles of our hydrochloric acid. So in determining the volume, we must do the following must take the volume and set that equal to the molds that we have Which was 0.01-0 moles of our nickel hydroxide. And multiply that by our multiple ratio which was For every one mole of Nickel Hydroxide. We have two moles of hydrochloric acid. We must then multiply that by the polarity of a hydrochloric acid and polarities in terms of most per liter. So we're going to say that for every one leader we have 0. moles of hydrochloric acid. And of course we want this answer in middle leader. So we have to use the conversion factor that for every one middle leader we have 10 to the negative third leaders And our units will all cancel out to give us the final answer of 160 mela leaders. And with that we've answered the question overall. I hope this helped. And until next time.