Write a balanced net ionic equation for the principal reaction in solutions of each of the following salts. In each case, identify the Brønsted–Lowry acids and bases and the conjugate acid–base pairs. (a) Na2CO3

Video transcript

Hello. In this problem we are asked to determine the predominant reaction that occurs in a solution of potassium sulfide and to provide the balance net ionic equation, we are asked to classify each species in the reaction of the bronze salary acid and base and then identify the conjugate acid base pairs. Let's begin by recalling that potassium sulfide, which is a salt, is a product of the reaction between an acid and a base. The acid component always contributes the an iron in the salt. So the acid would have been sulfurous acid and the base in the reaction always contributes the cat iron of the salt. So this would have been potassium hydroxide. Sulfurous acid is a weak acid and potassium hydroxide is a strong base. When we put our salt potassium sulfite into a quick solution. Since it is a soluble salt it will dissociate to form its ions. So potassium mines and cell fight and lines each of these, then can affect the solution making it acidic or basic. Let's begin by considering the potassium mine which is a main group. Metal Captain. Main group metal Carradine's. If they have a charge of three plus or greater they will create an acidic solution. If they have a charge of less than three plus they will create a neutral solution. So in our case we have potassium mine which has a charge of plus one. So it will create a neutral solution. Now let's look at our annan. So cell fight again was derived from a weak acid. So cell fight will function as a base being derived from a weak acid. It will undergo hydraulic sis, which means it will react with water and we will form then by cell fight and hydroxide ions. Hydroxide ions again illustrate the fact that we have a base basic solution. So the sulfide is the base. Water functions as an acid, so it donates a proton to the base so that we form cell fight, which is the conjugate acid of our base. And then we form hydroxide ions which are base and they are the conjugate base of our acid. So in this problem we are asked to identify the net ionic equation when potassium sulfite is put into solution. So this is our net ionic equation. We identified the acid and base on both the reactant and product side and we identified our to conjugate acid base pairs. Thanks for watching. Hope this helps