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Ch.15 - Chemical Equilibrium

Chapter 15, Problem 46

The following pictures represent the composition of the equi- librium mixture for the reaction A + B ∆ AB at 300 K and at 400 K.

Molecular representation of equilibrium mixtures for A + B ⇌ AB at 300 K and 400 K.

Is the reaction exothermic or endothermic? Explain using Le Châtelier's principle.

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Hello everyone today. We have the following problem to equilibrium states of the dissociation reaction. P Q two, P plus Q. At two different temperatures are shown in the diagrams below. There's one at 500 degrees kelvin and is one of 800 degrees kelvin. Identify whether the reaction is exo thermic or endo thermic. And justify your answer using less chandeliers principle. So let's look at each of these diagrams separately. So for our tea or a temperature that's equal to 500° Kelvin. We have the following molecules. We have P. Q. Which is going to be P plus Q together and this is going to equal seven. There are seven of these and there's three green, three purple spheres. So no matter what we designate the color as P or Q. There are three of each. Now if we look at our temperature for 800° Kelvin and we look at the molecules for this one, We can see that the PQ or the amount of green and purple molecules together is equal to four and our P And our Q is equal to six. So this is going to demonstrate that as we increased our temperature, the reaction proceeded forward. So we had a forward reaction and more of our P. Q. Dissociated to form more P molecules and more Q molecules. And so because we increased our temperature, we can say that heat was a reactant in this equation or this reaction. Therefore we can say that this is an indo thermic reaction. So the answer choice that best reflects this is. Andrew choice A. The reaction proceeds forward as the temperature increases, heat is considered as a reactant. Therefore, the reaction is endo thermic, and so with that we have answered the question overall, I hope this helped, and until next time.
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