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Ch.15 - Chemical Equilibrium

Chapter 15, Problem 91

An equilibrium mixture of N2, H2, and NH3 at 700 K con- tains 0.036 M N2 and 0.15 M H2. At this temperature, Kc for the reaction N21g2 + 3 H21g2 ∆ 2 NH31g2 is 0.29. What is the concentration of NH3?

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Hello. Everyone in this video. We're trying to determine the concentration of hcl were given this equilibrium immigration here. So first we're gonna go ahead and write out the essential information that were given to us in this problem, One of them being that the constant here, the equilibrium constant is 1 21. And at equilibrium Our concentration of H two is equal to the concentration of cl two And that concentration is 1. times 10 to the -3 molder. So let's first go ahead and recognize the equation for the equilibrium constant. So K. C. Is equal to was it ratio so not numerator here is the concentration of our products raised to the power of its coefficient over the concentration of our reactant raised to power of its coefficients. So then if we apply this to our equilibrium creation here, that's just The concentration of H. C. L. raised to the power of two. Over the concentration of H two multiplied by the concentration of Cl two. We're gonna go ahead and isolate H. C. L. So this right here and let's not forget that these two do equal each other. Alright, so how can isolate this? Is by multiplying both sides of this equation here by this denominator. So we first get hcl raised power of two. E. Going to the equilibrium constant times the concentration of H two times the concentration of cl two. And how we can officially isolate this concentration of hcl here is by square rooting both sides. So once we do so we get on the left side, just a concentration of Hcl and all this. So K. C. Times the concentration of H two times the concentration of cl two. We'll all be raised to a power of 1/2 or stress square braided. So once I have this equation here we can go ahead and actually plug in some numerical values. The concentration of hcl. So Casey Is going to be 121. The concentration of H two is given to us. This is 1.54 times 10 to the negative three moller. Where you said that these two actually equally teach each other so we can go ahead and just rewrite that 1.54 times 10 to the negative three. Alright, and this is all going to be square rooted. So once I put that into my calculator I get that the concentration of hcl here is equal to 1.69 times 10 to the negative to moller. And this right here is going to be my final answer for this problem.
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