To answer questions 13–15, refer to the mechanism: H2O21aq2 + I-1aq2¡OH-1aq2 + HOI1aq2 Slower, rate-determining HOI1aq2 + I-1aq2¡OH-1aq2 + I21aq2 Faster 2 OH-1aq2 + 2 H3O+1aq2¡4 H2O1l2 Faster Identify the catalyst and intermediate(s) in the mechanism. (LO 14.12, 14.16) (a) Catalyst = I-, intermediates = OH-, HOI (b) Catalyst = H3O+, intermediate = HOI (c) No catalyst, intermediate = I2 (d) No catalyst, intermediates = OH-, HOI

Video transcript

Hello everyone today. We have the following question. Consider the following reaction mechanism, determine the catalyst and the intermediates. So first let's define what a catalyst and what an intermediate are. So it cattle's essentially speeds up a chemical reaction and it's going to appear so a catalyst appears as a reactant and so it appears as a reactant in the first step. However, in the second step it appears as a product as a product, not necessarily the second step, but the last step. And so we can also define what an intermediate is. So an intermediate is essentially not a catalyst or product, but it's going to be some compound that ends up being canceled out. And so if you look at this equation for this chemical reaction, we can determine what the catalyst would be. So if we look closely in the first step, we have water here appearing as a reaction. And in the very last step we also have water appearing as well. So our catalyst, It's going to be water or H20. And so that gets rid of the answer choices A and B. Since we do have a catalyst next, we're going to look for our intermediate. And so that's going to involve canceling out anything that shows up on the reacting side, on the product side. So if we look at our H20. We see that it cancels out on the left here and then the last step there on the right, we also noticed how our hydroxide on the right and the first step. And then on the left. And the third step aside from that, we can also identify that we have our hipAA Cloris acid on the right here, the first step and also on the left side in the second step. And then we can conclude that there are no other similarities that are present. Until we look at our second step here and we find our hypo I. D. On the right and on the left of the 2nd and 3rd step. So we said our intermediates are things that are ending up being crossed out. So we have our hipAA Cloris acid, R. H. O. I. And we have our hydroxide. We aren't gonna count water because we've already concluded that water is our catalyst. And so the anti choice that best aligns with what we chose is going to be anti choice. See and with that we've answered the question overall. I hope this helped. And until next time.