Chlorite is reduced by bromide in acidic solution according to the following balanced equation: ClO2 -1aq2 + 4 Br-1aq2 + 4 H+1aq2S Cl-1aq2 + 2 Br21aq2 + 2 H2O1l2 (a) If Δ3Br24>Δt = 4.8 * 10-6 M>s, what is the value of Δ3ClO2 -4>Δt during the same time interval?

Video transcript

Hello everyone today, we have the phone problem. The balanced equation for the reaction of sodium sulfide with hydrogen bromide is as follows. What is the value of the change in the concentration for our hydrogen sulfide over the change in time? If the change in our hydrogen bromide over time is equal to 2.8 times 10 to the negative third molar per second during the same time period. So the first thing we wanna do is we want to recall the average rate of a reaction and what that equation would look like. So you would have the rate is equal to the change in the concentration of our reactant over the change in T or the change in time. And so we can simply do a rate to rate comparison based on a strict geometric coefficients. So it's also important to note That we have two moles of our hydrogen bromide indicated by the two coefficient for every one mall of our hydrogen sulfide. And so hydrogen sulfide doesn't have a coefficient and when it doesn't have a coefficient, it is assumed to be one. And so we can put our equation together by saying that we have our rate is equal to our change in our hydrogen sulfide over our change in time. So we have The value, we have the 2. Times 10 to the negative 3rd molar per second for our hydrogen bromide. And we can cancel out that hydrogen bromide, I would say this is hydrogen bromide, we can cancel that out with that comparison we made, which was we had one more Moeller per second For our hydrogen sulfide per every two Mueller over second of hydrogen bromide run our units of molar per second of hydrogen bromide cancel out. We're going to be left with 1.4 times 10 to the negative third, molar per second for hydrogen sulfide as our final answer overall, I hope this helped ahead until next time.