Assume that you have a cylinder with a movable piston. What would happen to the gas pressure inside the cylinder if you were to do the following? (a) Triple the Kelvin temperature while holding the volume constant

Video transcript

Hello everyone today we are being given the falling problem, consider a cylinder with a movable piston. How will the pressure of the gas in the cylinder change if the temperature in kelvin is doubled and at the same time keeping the volume constant. So the first thing you wanna do is you want to make note of our ideal gas law and our ideal gas law is our pressure times are volume is equal to the number of moles we have times are a gas constant times our temperature in kelvin and so it was already noted that our volume was kept constant so we can remove this variable and we can also assume that the number of moles and the gas constant is also going to remain constant. So then we're just left with pressure and temperature and from here we can know an important law, an important gas law and its relationship. So here we have the gay loose Acs law in that states that our pressure is directly proportional to our temperature. So I'm gonna write up here that this little sign here means directly proportional meaning as one value increases, the other increases as well. And so it was noted that the temperature is doubled. So if we have our pressure here and we double the temperature, this is therefore going to lead to our answer and that our pressure is also going to double And so our final answer will be that our pressure is doubled when our temperature is also doubled. And with that we've answered the question overall. I hope this helped. And until next time