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Ch.9 - Thermochemistry: Chemical Energy
Chapter 9, Problem 82

Instant cold packs used to treat athletic injuries contain solid NH4NO3 and a pouch of water. When the pack is squeezed, the pouch breaks and the solid dissolves, lowering the tem-perature because of the endothermic reaction NH4NO31s2 ¡ NH4NO31aq2 ∆H = +25.7 kJ What is the final temperature in a squeezed cold pack that contains 50.0 g of NH4NO3 dissolved in 125 mL of water? Assume a specific heat of 4.18 J/(g C) for the solution, an initial temperature of 25.0 °C, and no heat transfer between the cold pack and the environment.

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1
Calculate the moles of NH4NO3 used by using its molar mass. The molar mass of NH4NO3 is approximately 80 g/mol.
Determine the total heat absorbed by the solution using the enthalpy change of the reaction (∆H). Multiply the moles of NH4NO3 by the ∆H value given (+25.7 kJ/mol).
Convert the heat absorbed from kJ to Joules to match the units of specific heat (1 kJ = 1000 J).
Calculate the change in temperature using the formula: ∆T = q / (m * c), where q is the heat absorbed in Joules, m is the mass of the solution (mass of water plus mass of NH4NO3), and c is the specific heat of the solution (4.18 J/(g°C)).
Subtract the change in temperature (∆T) from the initial temperature of the solution to find the final temperature of the cold pack.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Endothermic Reactions

Endothermic reactions absorb heat from their surroundings, resulting in a decrease in temperature. In the case of the cold pack, the dissolution of NH4NO3 is an endothermic process, which means it requires energy to break the ionic bonds in the solid, leading to a cooling effect. This concept is crucial for understanding why the temperature drops when the pack is activated.
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Specific Heat Capacity

Specific heat capacity is the amount of heat required to raise the temperature of a unit mass of a substance by one degree Celsius. For the solution in the cold pack, the specific heat is given as 4.18 J/(g°C). This property is essential for calculating how much the temperature of the solution will change when a certain amount of heat is absorbed during the dissolution of NH4NO3.
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Heat Transfer and Conservation of Energy

The principle of conservation of energy states that energy cannot be created or destroyed, only transformed. In the context of the cold pack, the heat absorbed by the dissolution of NH4NO3 must equal the heat lost by the water in the pack. This relationship allows us to set up an equation to find the final temperature of the solution after the cold pack is activated.
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Related Practice
Textbook Question
Titanium metal is used as a structural material in many high-tech applications, such as in jet engines. what is the specific heat of titanium in J/(g·°C) if it takes 89.7 J to raise the temeprature of a 33.0 g block of 5.20 °C? What is the molar heat capacity of titanium J/(mol·°C)?
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Textbook Question
Assuming that Coca-Cola has the saem specific heat as water [4.18 J/(g C)], calculate the amount of heat in kilojoules transferred when one can (about 350 g) is cooled from 25 C to 3 C.
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Textbook Question
Calculate the amount of heat required to raise the tempera- ture of 250.0 g (approximately 1 cup) of hot chocolate from 25.0 °C to 80.0 °C. Assume hot chocolate has the same spe-cific heat as water 34.18 J>1g °C24.
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Textbook Question
Instant hot packs contain a solid and a pouch of water. When the pack is squeezed, the pouch breaks and the solid dis- solves, increasing the temperature because of the exothermic reaciton. The following reaction is used to make a hot pack: H2O LiCl1s2 ¡ Li 1aq2 + Cl 1aq2 ∆H = -36.9 kJ. What is the final temperature in a squeezed hot pack that contains 25.0 g of LiCl dissolved# in 125 mL of water? Assume a specific heat of 4.18 J>1g °C2 for the solution, an initial temperature of 25.0 °C, and no heat transfer between the hot pack and the environment.
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Textbook Question
When 0.187 g of benzene, C6H6, is burned in a bomb calorimeter the temperature rises by 3.45 °C. If the heat capacity of the calorimeter is 2.46 kJ>°C, calculate the combustion energy 1∆E2 for benzene in units of kJ/g and kJ/mol.
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Textbook Question
When 1.50 g of magnesium metal is allowed to react with 200 mL of 6.00 M aqueous HCl, the temperature rises from 25.0 °C to 42.9 °C. Calculate ΔH in kilojoules for the reaction, assumign that the heat capacity of the calorimeter is 776 J/°C, that the specific heat of the final soltuion is the same as that of water [4.18 J(g·°C)] and that the density of the solution is 1.00 g/mL
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