Iodine forms the acid anhydride I2O5. Write a balanced equation for the reaction of this anhydride with water, and name the acid that is formed.

Verified step by step guidance

1. Identify the acid anhydride: Iodine forms the acid anhydride \( \text{I}_2\text{O}_5 \). An acid anhydride is a non-metal oxide that reacts with water to form an acid.
2. Determine the type of acid formed: When \( \text{I}_2\text{O}_5 \) reacts with water, it forms an oxyacid. The general reaction for an acid anhydride with water is \( \text{X}_2\text{O}_n + \text{H}_2\text{O} \rightarrow 2\text{HXO}_m \).
3. Write the unbalanced chemical equation: Combine \( \text{I}_2\text{O}_5 \) with water (\( \text{H}_2\text{O} \)) to form the acid \( \text{HIO}_3 \). The unbalanced equation is: \( \text{I}_2\text{O}_5 + \text{H}_2\text{O} \rightarrow \text{HIO}_3 \).
4. Balance the chemical equation: Ensure that the number of atoms of each element is the same on both sides of the equation. The balanced equation is: \( \text{I}_2\text{O}_5 + \text{H}_2\text{O} \rightarrow 2\text{HIO}_3 \).
5. Name the acid formed: The acid formed in this reaction is iodic acid, \( \text{HIO}_3 \).