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Ch.22 - The Main Group Elements
Chapter 22, Problem 159

What is the electron-dot structure and geometry of XeO3?

Verified step by step guidance
1
Step 1: Determine the total number of valence electrons available. Xenon (Xe) has 8 valence electrons, and each oxygen (O) has 6 valence electrons. Since there are three oxygen atoms, the total number of valence electrons is 8 + (3 * 6).
Step 2: Draw the skeletal structure of the molecule. Place the xenon (Xe) atom in the center and connect it to the three oxygen (O) atoms with single bonds.
Step 3: Distribute the remaining valence electrons to satisfy the octet rule for each oxygen atom. Start by placing lone pairs on the oxygen atoms until each has 8 electrons (including the bonding electrons).
Step 4: Check if the central xenon atom has a complete octet. If not, consider forming double bonds between xenon and oxygen atoms to ensure that xenon also satisfies the octet rule.
Step 5: Determine the molecular geometry using VSEPR theory. Count the number of bonding pairs and lone pairs around the central xenon atom to predict the shape of the molecule. XeO3 has three bonding pairs and one lone pair, leading to a trigonal pyramidal geometry.