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Ch.2 - Atoms, Molecules & Ions
Chapter 2, Problem 83

The atomic weight of carbon (12.011) is approximately 12 times that of hydrogen (1.008). (a) Show how you can use this knowledge to calculate pos-sible formulas for benzene, ethane, and ethylene (Prob-lem 2.82).

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Identify the molecular formulas for benzene, ethane, and ethylene: Benzene (C6H6), Ethane (C2H6), Ethylene (C2H4).
Calculate the molar mass of each compound using the atomic weights: For benzene, multiply the number of carbon atoms by the atomic weight of carbon and the number of hydrogen atoms by the atomic weight of hydrogen, then sum these values.
Repeat the calculation for ethane: Multiply the number of carbon atoms by the atomic weight of carbon and the number of hydrogen atoms by the atomic weight of hydrogen, then sum these values.
Repeat the calculation for ethylene: Multiply the number of carbon atoms by the atomic weight of carbon and the number of hydrogen atoms by the atomic weight of hydrogen, then sum these values.
Compare the calculated molar masses with the known atomic weights to verify the possible formulas for benzene, ethane, and ethylene.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Molecular Formula

A molecular formula represents the number and type of atoms in a molecule. For hydrocarbons like benzene, ethane, and ethylene, the formula indicates the ratio of carbon (C) to hydrogen (H) atoms. Understanding how to derive these formulas based on atomic weights and the number of atoms is essential for calculating possible molecular structures.
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Atomic Weight

Atomic weight is the weighted average mass of an element's isotopes, measured in atomic mass units (amu). For carbon, the atomic weight is approximately 12.011 amu, while for hydrogen, it is about 1.008 amu. This concept is crucial for determining the mass contributions of each element in a compound, which aids in calculating molecular formulas.
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Empirical vs. Molecular Formula

The empirical formula represents the simplest whole-number ratio of atoms in a compound, while the molecular formula shows the actual number of atoms. For example, benzene has a molecular formula of C6H6, but its empirical formula is CH. Understanding the distinction between these formulas is important for accurately determining the composition of organic compounds based on their atomic weights.
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Related Practice
Textbook Question
In methane, one part hydrogen combines with three parts carbon by mass. If a sample of a compound containing only carbon and hydrogen contains 32.0 g of carbon and 8.0 g of hydrogen, could the sample be methane? If the sample is not methane, show that the law of multiple proportions is fol-lowed for methane and this other substance.
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Textbook Question
In borane, one part hydrogen combines with 3.6 parts boron by mass. A compound containing only hydrogen and boron contains 6.0 g of hydrogen and 43.2 g of boron. Could this compound be borane? If it is not borane, show that the law of multiple proportions is followed for borane and this other substance.
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Textbook Question
Benzene, ethane, and ethylene are just three of a large num-ber of hydrocarbons—compounds that contain only carbon and hydrogen. Show how the following data are consistent with the law of multiple proportions.
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Textbook Question
Two compounds containing carbon and oxygen have the following percent composition by mass. Compound 1: 42.9% carbon and 57.1% oxygen Compound 2: 27.3% carbon and 72.7% oxygen Show that the law of multiple proportions is followed. If the formula of the first compound is CO, what is the formula of the second compound?
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Open Question
In addition to carbon monoxide (CO) and carbon dioxide (CO2), there is a third compound of carbon and oxygen called carbon suboxide. If a 2.500 g sample of carbon suboxide contains 1.32 g of C and 1.18 g of O, show that the law of multiple proportions is followed. What is a possible formula for carbon suboxide?
Open Question
The results from Thomson’s cathode-ray tube experiment led to the discovery of which subatomic particle?