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Ch.15 - Chemical Equilibrium
Chapter 15, Problem 115

The reaction of fumarate with water to form L-malate is catalyzed by the enzyme fumarase; Kc = 3.3 at 37°C. When a reaction mixture with [fumarate] = 1.56 * 10-3 M and [l -malate] = 2.27 * 10-3 M comes to equilibrium in the presence of fumarase at 37 °C, what are the equilibrium concentrations of fumarate and L-malate? (Water can be omit- ted from the equilibrium equation because its concentration in dilute solutions is essentially the same as that in pure water.)

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Step 1: Write down the equilibrium expression for the reaction. Since water is not included in the equilibrium expression, the equilibrium constant Kc for the reaction is given by [L-malate]/[fumarate].
Step 2: Set up the ICE (Initial, Change, Equilibrium) table. Initially, [fumarate] = 1.56 * 10^-3 M and [L-malate] = 2.27 * 10^-3 M. Let x be the change in concentration of fumarate and L-malate as the reaction proceeds to equilibrium.
Step 3: Write the equilibrium concentrations in terms of x. The equilibrium concentration of fumarate will be (1.56 * 10^-3 - x) M and the equilibrium concentration of L-malate will be (2.27 * 10^-3 + x) M.
Step 4: Substitute the equilibrium concentrations into the equilibrium expression and set it equal to the given Kc value of 3.3. Solve the resulting equation for x.
Step 5: Substitute the value of x back into the expressions for the equilibrium concentrations of fumarate and L-malate to find their values at equilibrium.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Equilibrium Constant (Kc)

The equilibrium constant (Kc) is a numerical value that expresses the ratio of the concentrations of products to reactants at equilibrium for a given reaction at a specific temperature. In this case, Kc = 3.3 indicates that at equilibrium, the concentration of L-malate is 3.3 times greater than that of fumarate. Understanding Kc is essential for calculating the equilibrium concentrations of reactants and products.
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Le Chatelier's Principle

Le Chatelier's Principle states that if a dynamic equilibrium is disturbed by changing the conditions, the system will adjust to counteract the change and restore a new equilibrium. This principle helps predict how changes in concentration, temperature, or pressure will affect the position of equilibrium, which is crucial for understanding how the concentrations of fumarate and L-malate will shift in response to their initial concentrations.
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Reaction Quotient (Q)

The reaction quotient (Q) is a measure of the relative concentrations of products and reactants at any point in time during a reaction. It is calculated using the same formula as Kc but with the current concentrations. By comparing Q to Kc, one can determine the direction in which the reaction will proceed to reach equilibrium, which is vital for solving the problem of finding the equilibrium concentrations of fumarate and L-malate.
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Related Practice
Textbook Question
The equilibrium constant Kc for the reaction N21g2 + 3 H21g2 ∆ 2 NH31g2 is 4.20 at 600 K. When a quantity of gaseous NH3 was placed in a 1.00-L reaction vessel at 600 K and the reaction was allowed to reach equilibrium, the vessel was found to contain 0.200 mol of N2. How many moles of NH3 were placed in the vessel?
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Open Question
At 45 °C, Kc = 0.619 for the reaction N2O4(g) ⇌ 2 NO2(g). If 46.0 g of N2O4 is introduced into an empty 2.00-L container, what are the partial pressures of NO2 and N2O4 after equilibrium has been achieved at 45 °C?
Open Question
When 9.25 g of ClF3 was introduced into an empty 2.00-L container at 700.0 K, 19.8% of the ClF3 decomposed to give an equilibrium mixture of ClF3, ClF, and F2. ClF3 (g) ⇌ ClF (g) + F2 (g). (a) What is the value of the equilibrium constant Kc at 700.0 K? (b) What is the value of the equilibrium constant Kp at 700.0 K? (c) In a separate experiment, 39.4 g of ClF3 was introduced into an empty 2.00-L container at 700.0 K. What are the concentrations of ClF3, ClF, and F2 when the mixture reaches equilibrium?
Open Question
Calculate the equilibrium concentrations of SO2, Cl2, and SO2Cl2 at 298 K if the initial concentrations are [SO2] = 1.50 M and [Cl2] = 0.85 M. The equilibrium constant Kc for the reaction SO2(g) + Cl2(g) ⇌ SO2Cl2(g) is 8.40 × 10^-3 at 298 K.
Open Question
Calculate the equilibrium concentrations of H2O(g), Cl2(g), HCl(g), and O2(g) at 298 K if the initial concentrations are [H2O] = 0.050 M and [Cl2] = 0.100 M. The equilibrium constant Kc for the reaction H2O(g) + Cl2(g) ⇌ 2 HCl(g) + O2(g) is 8.96 × 10^-9 at 298 K.
Textbook Question

Consider the following equilibrium: Ag+ (aq) + Cl-(aq) → AgCl(s) Use Le Châtelier's principle to predict how the amount of solid silver chloride will change when the equilibrium is disturbed by: (c) Adding NO3, which reacts with Ag+ to form the complex ion Ag(NH3)2+

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