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Ch.14 - Chemical Kinetics
Chapter 14, Problem 9

Chlorine monoxide (ClO) decomposes at room temperature according to the reaction 2 ClO1g2¡Cl21g2 + O21g2 The concentration of ClO was monitored over time, and three graphs were made: Graph showing concentration of ClO over time, decreasing from 0.03 to 0.015 mol/L.
Graph showing the natural logarithm of ClO concentration over time, linear decline indicating first-order reaction.
What is the rate law for the reaction? (LO 14.9) (a) Rate = k (b) Rate = k3ClO4 (c) Rate = k3ClO42 (d) Rate = k3ClO43 M14_MCMU6230_

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Examine the first graph, which shows the concentration of ClO over time. Notice that the concentration decreases over time.
Examine the second graph, which shows the natural logarithm of the ClO concentration over time. Notice that this graph is a straight line.
Recall that a straight line in a plot of ln[ClO] versus time indicates a first-order reaction.
For a first-order reaction, the rate law is given by Rate = k[ClO].
Therefore, the rate law for the decomposition of ClO is Rate = k[ClO].

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Reaction Order

The reaction order refers to the power to which the concentration of a reactant is raised in the rate law of a chemical reaction. It indicates how the rate of reaction depends on the concentration of reactants. For example, a first-order reaction means that the rate is directly proportional to the concentration of one reactant, while a second-order reaction involves the square of the concentration. Understanding the reaction order is crucial for determining the rate law.
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Rate Law

The rate law is an equation that relates the rate of a chemical reaction to the concentration of its reactants. It is typically expressed in the form Rate = k[A]^m[B]^n, where k is the rate constant, and m and n are the orders of the reaction with respect to reactants A and B, respectively. The rate law provides insight into the mechanism of the reaction and is determined experimentally, often through concentration vs. time data.
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First-Order Reactions

First-order reactions are characterized by a linear relationship between the natural logarithm of the concentration of a reactant and time. This means that as the concentration decreases, the rate of reaction remains proportional to the concentration of the reactant. The provided graph of the natural logarithm of ClO concentration over time indicates a straight line, confirming that the decomposition of ClO follows first-order kinetics, which is essential for determining the correct rate law.
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Related Practice
Textbook Question
Use the following equation and graph to answer questions 1 and 2. Hydrogen iodide decomposes at 410 °C, according the reaction: 2 HI1g2¡H21g2 + I21g2 The graph shows how the concentration of HI changes over time. What is the average rate of loss of HI over the time period 0–40 s (LO 14.1) (a) 7.5 * 10-3 M>s (b) 4.8 * 10-3 M>s (c) 3.0 * 10-2 M>s (d) 3.5 * 10-3 M>s
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Textbook Question
The gas phase decomposition of HI has the following rate law: 2 HI1g2¡H21g2 + I21g2 Rate = k3HI42 At 443 °C, k = 30.1 M-1 min-1. If the initial concentration of HI is 0.010 M, what is the concentration after 1.5 hours? (LO 14.8) (a) 6.9 * 10-3 M (b) 1.8 * 10-3 M (c) 3.6 * 10-4 M (d) 8.9 * 10-4 M
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Textbook Question
A key reaction in the upper atmosphere is O31g2 + O1g2 ¡ 2 O21g2 For this process, the energy of activation for the forward reaction, Ea1fwd2, is 19 kJ/mol, and the enthalpy change for the reaction, ΔHrxn, is -392 kJ>mol. What is the energy of activation for the reverse reaction, Ea1reverse2? (LO 14.10) (a) 411 kJ/mol (b) 392 kJ/mol (c) 373 kJ/mol (d) 196 kJ/mol
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Textbook Question
To answer questions 13–15, refer to the mechanism: H2O21aq2 + I-1aq2¡OH-1aq2 + HOI1aq2 Slower, rate-determining HOI1aq2 + I-1aq2¡OH-1aq2 + I21aq2 Faster 2 OH-1aq2 + 2 H3O+1aq2¡4 H2O1l2 Faster Identify the catalyst and intermediate(s) in the mechanism. (LO 14.12, 14.16) (a) Catalyst = I-, intermediates = OH-, HOI (b) Catalyst = H3O+, intermediate = HOI (c) No catalyst, intermediate = I2 (d) No catalyst, intermediates = OH-, HOI
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Textbook Question
(b) Write the balanced reaction that corresponds to the data in the graph.

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