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Ch.14 - Chemical Kinetics
Chapter 14, Problem 11

A key reaction in the upper atmosphere is O31g2 + O1g2 ¡ 2 O21g2 For this process, the energy of activation for the forward reaction, Ea1fwd2, is 19 kJ/mol, and the enthalpy change for the reaction, ΔHrxn, is -392 kJ>mol. What is the energy of activation for the reverse reaction, Ea1reverse2? (LO 14.10) (a) 411 kJ/mol (b) 392 kJ/mol (c) 373 kJ/mol (d) 196 kJ/mol

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Identify the given values: the activation energy for the forward reaction, \( E_{a, \text{fwd}} = 19 \text{ kJ/mol} \), and the enthalpy change for the reaction, \( \Delta H_{\text{rxn}} = -392 \text{ kJ/mol} \).
Recall the relationship between the activation energies of the forward and reverse reactions: \( E_{a, \text{reverse}} = E_{a, \text{fwd}} + \Delta H_{\text{rxn}} \).
Substitute the given values into the equation: \( E_{a, \text{reverse}} = 19 \text{ kJ/mol} + (-392 \text{ kJ/mol}) \).
Simplify the expression to find \( E_{a, \text{reverse}} \).
Compare the calculated \( E_{a, \text{reverse}} \) with the provided options to determine the correct answer.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Activation Energy

Activation energy (Ea) is the minimum energy required for a chemical reaction to occur. It represents the energy barrier that reactants must overcome to transform into products. In this context, the forward reaction has a specific activation energy, which is crucial for understanding how the reaction proceeds and how it can be influenced by temperature and catalysts.
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Enthalpy Change (ΔH)

Enthalpy change (ΔH) is the heat content change during a chemical reaction at constant pressure. A negative ΔH indicates that the reaction is exothermic, meaning it releases energy. This value is essential for calculating the activation energy of the reverse reaction, as it helps determine the energy difference between reactants and products.
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Energy Profile Diagram

An energy profile diagram visually represents the energy changes during a chemical reaction, showing the energy of reactants, products, and the activation energies for both forward and reverse reactions. Understanding this diagram helps in calculating the activation energy for the reverse reaction by using the relationship between the activation energies and the enthalpy change of the reaction.
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Related Practice
Textbook Question
Use the following equation and graph to answer questions 1 and 2. Hydrogen iodide decomposes at 410 °C, according the reaction: 2 HI1g2¡H21g2 + I21g2 The graph shows how the concentration of HI changes over time. What is the average rate of loss of HI over the time period 0–40 s (LO 14.1) (a) 7.5 * 10-3 M>s (b) 4.8 * 10-3 M>s (c) 3.0 * 10-2 M>s (d) 3.5 * 10-3 M>s
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Textbook Question
The gas phase decomposition of HI has the following rate law: 2 HI1g2¡H21g2 + I21g2 Rate = k3HI42 At 443 °C, k = 30.1 M-1 min-1. If the initial concentration of HI is 0.010 M, what is the concentration after 1.5 hours? (LO 14.8) (a) 6.9 * 10-3 M (b) 1.8 * 10-3 M (c) 3.6 * 10-4 M (d) 8.9 * 10-4 M
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Textbook Question
Chlorine monoxide (ClO) decomposes at room temperature according to the reaction 2 ClO1g2¡Cl21g2 + O21g2 The concentration of ClO was monitored over time, and three graphs were made:

What is the rate law for the reaction? (LO 14.9) (a) Rate = k (b) Rate = k3ClO4 (c) Rate = k3ClO42 (d) Rate = k3ClO43 M14_MCMU6230_
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Textbook Question
To answer questions 13–15, refer to the mechanism: H2O21aq2 + I-1aq2¡OH-1aq2 + HOI1aq2 Slower, rate-determining HOI1aq2 + I-1aq2¡OH-1aq2 + I21aq2 Faster 2 OH-1aq2 + 2 H3O+1aq2¡4 H2O1l2 Faster Identify the catalyst and intermediate(s) in the mechanism. (LO 14.12, 14.16) (a) Catalyst = I-, intermediates = OH-, HOI (b) Catalyst = H3O+, intermediate = HOI (c) No catalyst, intermediate = I2 (d) No catalyst, intermediates = OH-, HOI
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Textbook Question
(b) Write the balanced reaction that corresponds to the data in the graph.

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Textbook Question

The following reaction is first order in A (red spheres) and first order in B (blue spheres): A + B → Products Rate = k[A][B]

(a) What are the relative rates of this reaction in vessels (1)–(4)? Each vessel has the same volume.

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