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Ch.13 - Solutions & Their Properties
Chapter 13, Problem 118

What is the osmotic pressure in atmospheres you would expect for each of the following solutions? (a) 5.00 g of NaCl in 350.0 mL of aqueous solution at 50 °C (b) 6.33 g of sodium acetate, CH3CO2Na, in 55.0 mL of aqueous solution at 10 °C

Verified step by step guidance
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Step 1: Calculate the molarity of the solution. First, determine the number of moles of solute. For NaCl, use its molar mass to convert grams to moles. Similarly, do this for sodium acetate, CH3CO2Na.
Step 2: Convert the volume of the solution from milliliters to liters, as molarity is expressed in moles per liter.
Step 3: Use the formula for molarity (M = moles of solute / liters of solution) to find the molarity of each solution.
Step 4: Apply the formula for osmotic pressure: \( \Pi = iMRT \), where \( i \) is the van 't Hoff factor (2 for NaCl and 1 for sodium acetate), \( M \) is the molarity, \( R \) is the ideal gas constant (0.0821 L·atm/mol·K), and \( T \) is the temperature in Kelvin.
Step 5: Convert the given temperatures from Celsius to Kelvin by adding 273.15, then substitute all known values into the osmotic pressure formula to calculate the osmotic pressure for each solution.
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