Skip to main content
Ch.13 - Solutions & Their Properties
Chapter 13, Problem 116

A solution of citric acid, C6H8O7, in 50.0 g of acetic acid has a boiling point elevation of ΔT = 1.76 °C. What is the molality of the solution if the molal boilin# g-point-elevation constant for acetic acid is Kb = 3.07 1°C kg2>mol.

Verified step by step guidance
1
Identify the formula for boiling point elevation: \( \Delta T = K_b \times m \), where \( \Delta T \) is the boiling point elevation, \( K_b \) is the ebullioscopic constant, and \( m \) is the molality.
Rearrange the formula to solve for molality \( m \): \( m = \frac{\Delta T}{K_b} \).
Substitute the given values into the formula: \( \Delta T = 1.76 \, ^\circ\text{C} \) and \( K_b = 3.07 \, ^\circ\text{C} \, \text{kg/mol} \).
Calculate the molality \( m \) using the rearranged formula.
Remember that molality \( m \) is defined as moles of solute per kilogram of solvent, so the result will be in units of mol/kg.

Verified Solution

Video duration:
2m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Boiling Point Elevation

Boiling point elevation is a colligative property that describes how the boiling point of a solvent increases when a solute is dissolved in it. This phenomenon occurs because the presence of solute particles disrupts the solvent's ability to evaporate, requiring a higher temperature to reach the boiling point. The relationship is quantified by the formula ΔT = Kb * m, where ΔT is the boiling point elevation, Kb is the boiling point elevation constant, and m is the molality of the solution.
Recommended video:
Guided course
03:05
Boiling Point Elevation

Molality

Molality (m) is a measure of the concentration of a solute in a solution, defined as the number of moles of solute per kilogram of solvent. It is particularly useful in colligative property calculations because it directly relates to the number of solute particles in a given mass of solvent, making it independent of temperature and volume changes. The formula for calculating molality is m = moles of solute / mass of solvent (in kg).
Recommended video:

Colligative Properties

Colligative properties are properties of solutions that depend on the number of solute particles in a given amount of solvent, rather than the identity of the solute. These properties include boiling point elevation, freezing point depression, vapor pressure lowering, and osmotic pressure. Understanding colligative properties is essential for predicting how the addition of solute affects the physical properties of a solvent, which is crucial in various chemical applications.
Recommended video:
Guided course
01:26
Colligative Properties
Related Practice
Open Question
What is the mole fraction of each component in the liquid mixture in Problem 13.111, and what is the mole fraction of each component in the vapor at 25 °C?
Textbook Question
A solution prepared by dissolving 5.00 g of aspirin, C9H8O4, in 215 g of chloroform has a normal boiling point that is elevated by ΔT = 0.47 °C over that of pure chloro- form. What is the value of the molal boiling-point-elevation constant for chloroform?
491
views
Textbook Question
A solution prepared by dissolving 3.00 g of ascorbic acid (vitamin C, C6H8O6) in 50.0 g of acetic acid has a freez- ing point that is depressed by ΔT = 1.33 °C below that ofpure acetic acid. What is the value of the molal freezing- point-depression constant for acetic acid?
458
views
Open Question
What is the normal boiling point in °C of ethyl alcohol if a solution prepared by dissolving 26.0 g of glucose (C6H12O6) in 285 g of ethyl alcohol has a boiling point of 79.1 °C? See Table 13.4 to find Kb for ethyl alcohol.
Open Question
What is the osmotic pressure in atmospheres you would expect for each of the following solutions? (a) 5.00 g of NaCl in 350.0 mL of aqueous solution at 50 °C (b) 6.33 g of sodium acetate, CH3CO2Na, in 55.0 mL of aqueous solution at 10 °C
Textbook Question
What osmotic pressure in mm Hg would you expect for an aqueous solution of 11.5 mg of insulin 1mol. weight = 59902 in 6.60 mL of solution at 298 K? What would the height of the water column be in meters? The density of mercury is 13.534 g/mL at 298 K.
749
views