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Ch.9 - Molecular Geometry and Bonding Theories

Chapter 9, Problem 30a

Give the approximate values for the indicated bond angles in the following molecules: (a)

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Hi everyone. So he asked given the construction of hydrocarbon Which letters represent 120° by an angle in the compound, we have the carbons labeled A through E. If we look at carbon A. This has 12 electron groups around it. So this is gonna have a linear geometry And we have no long pairs. For the bond angle is gonna be 180°. The carbon B. We have 12 and two hydrogen coming off it. So there's two more electron groups for a total of four electron groups. So this is tetra hydro And there's no long pairs. It's gonna have a bond over 109.5 degrees for carbon C. We have one two. And how did you come out of it for a total of three electron groups? So that's gonna be triggering a planer geometry And there's no long pairs who has a bond angle of 120° carbon di I have one too And a hydrogen here. A total of three electron groups. And this is also triggered a planner And there's no lone pairs. So it has a bond angle of 120° for carbon E. We have 12 and hydrogen here for a total of three electron groups around it. It's also gonna be tribunal cleaner And has a bond angle of 120°. So the letters that represent 120° bond angle in the compound gonna be see and eat. Thanks for watching my video and I hope it was up for