A molecule with formula C4H3NO has the connectivity shown in the figure. After the Lewis structure of the molecule is completed, how many of each of the following are there in the molecule:

a. single bonds,

b. double bonds,

c. triple bonds,

d. nonbonding pairs? [Sections 8.3 and 8.5]

Video transcript

hey everyone, we're shown the connectivity of atoms in the oxydol molecule and were asked to complete the lewiS structure and to determine the number of sigma and pI bonds. Now we've learned that single bonds will contain sigma bonds while double bonds will contain a sigma plus a pi bond, a triple bond will contain a sigma plus two pi bonds. Now that we have this in mind, we can use this as reference when we determine the number of sigma and pi bonds. So let's go ahead and complete our structure first. We need to complete the octet of each atom in order to do so we need to add a double bond between our two carbons and a double bond between our carbon and nitrogen. We also have to add a lone pair on our nitrogen and two lone pairs on our oxygen. Now we have the complete lewis structure of oxydol. Now to answer the second part of our question, I'm going to go ahead and highlight our single bonds as pink are double bonds as blue. And our triple bonds as yellow counting are single bonds. First We have 1, 2, 3, 4, 5 and six. So we have a total of six single bonds. Now let's go ahead and count our double bonds. We have one, two. We only have two double buttons now to determine the number of sigma and pi bonds, we know that our six single bonds are going to give us six sigma bonds while our two double bonds are going to give us two sigma bonds Plus two Pi bonds in total, we have six plus two sigma bonds, which will get us to eight sigma bonds, And we have two pi bonds. And this is going to be our final answer since we also didn't have any trouble bonds. Now, I hope that made sense and let us know if you have any questions.