Skip to main content
Ch.6 - Electronic Structure of Atoms
Chapter 6, Problem 42a

The Lyman series of emission lines of the hydrogen atom are those for which nf = 1. (a) Determine the region of the electromagnetic spectrum in which the lines of the Lyman series are observed.

Verified step by step guidance
1
Identify the Lyman series in the context of the hydrogen atom's emission spectrum, where the final energy level (n_f) is 1.
Recall that the Lyman series involves electronic transitions from higher energy levels (n_i > 1) to the n_f = 1 level.
Use the Rydberg formula for hydrogen: \( \frac{1}{\lambda} = R_H \left( \frac{1}{1^2} - \frac{1}{n_i^2} \right) \), where \( R_H \) is the Rydberg constant and \( n_i \) is the initial energy level.
Recognize that the Lyman series transitions result in the release of photons with wavelengths in the ultraviolet (UV) region of the electromagnetic spectrum.
Conclude that the Lyman series lines are observed in the ultraviolet region, as these transitions involve high energy changes.

Verified Solution

Video duration:
6m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Lyman Series

The Lyman series refers to a set of spectral lines corresponding to transitions of electrons in a hydrogen atom from higher energy levels (n ≥ 2) to the lowest energy level (n = 1). These transitions result in the emission of ultraviolet light, which is a key feature of hydrogen's emission spectrum.
Recommended video:
Guided course
02:02
Activity Series Chart

Electromagnetic Spectrum

The electromagnetic spectrum encompasses all types of electromagnetic radiation, arranged by wavelength or frequency. It includes gamma rays, X-rays, ultraviolet light, visible light, infrared radiation, microwaves, and radio waves. The Lyman series specifically falls within the ultraviolet region of this spectrum.
Recommended video:
Guided course
02:53
Electromagnetic Spectrum

Energy Level Transitions

Energy level transitions in an atom occur when an electron moves between different energy states. When an electron drops from a higher energy level to a lower one, it releases energy in the form of a photon. The energy of the emitted photon corresponds to the difference in energy between the two levels, determining the wavelength and thus the position in the electromagnetic spectrum.
Recommended video:
Guided course
03:12
Transition Metals
Related Practice
Textbook Question

a. Using Equation 6.5, calculate the energy of an electron in the hydrogen atom when n = 2 and when n = 6. Calculate the wavelength of the radiation released when an electron moves from n = 6 to n = 2.

3
views
Textbook Question

The visible emission lines observed by Balmer all involved nf = 2. (a) Which of the following is the best explanation of why the lines with nf = 3 are not observed in the visible portion of the spectrum: (i) Transitions to nf = 3 are not allowed to happen, (ii) transitions to nf = 3 emit photons in the infrared portion of the spectrum, (iii) transitions to nf = 3 emit photons in the ultraviolet portion of the spectrum, or (iv) transitions to nf = 3 emit photons that are at exactly the same wavelengths as those to nf = 2.

1104
views
Textbook Question

The visible emission lines observed by Balmer all involved nf = 2. (b) Calculate the wavelengths of the first three lines in the Balmer series—those for which ni = 3, 4, and 5—and identify these lines in the emission spectrum shown in Figure 6.11.

1280
views
Textbook Question

The Lyman series of emission lines of the hydrogen atom are those for which nf = 1. (b) Calculate the wavelengths of the first three lines in the Lyman series—those for which ni = 2, 3, and 4.

2645
views
Textbook Question

One of the emission lines of the hydrogen atom has a wavelength of 93.07 nm. a. In what region of the electromagnetic spectrum is this emission found?

2
views
Textbook Question

One of the emission lines of the hydrogen atom has a wavelength of 93.07 nm. b. Determine the initial and final values of n associated with this emission.

1
views