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Ch.14 - Chemical Kinetics
Chapter 14, Problem 39a

(a) For the generic reaction A S B what quantity, when graphed versus time, will yield a straight line for a first-order reaction?

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Identify the order of the reaction given in the problem, which is a first-order reaction.
Recall that for a first-order reaction, the rate of reaction is directly proportional to the concentration of one reactant. The rate law can be expressed as: \(rate = k[A]\), where \(k\) is the rate constant and \([A]\) is the concentration of reactant A.
Understand that for a first-order reaction, the natural logarithm of the concentration of the reactant versus time will yield a straight line. This is derived from the integrated rate law for a first-order reaction: \(\ln[A] = -kt + \ln[A]_0\), where \([A]_0\) is the initial concentration of A.
Set up the graph with time (t) on the x-axis and the natural logarithm of the concentration of A (\(\ln[A]\)) on the y-axis.
Plot the data points for \(\ln[A]\) versus time and draw the best fit line. The slope of this line will be equal to \(-k\), and the y-intercept will be \(\ln[A]_0\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

First-Order Reactions

First-order reactions are chemical reactions where the rate is directly proportional to the concentration of one reactant. This means that as the concentration of the reactant decreases, the rate of reaction also decreases in a linear fashion. The mathematical representation of a first-order reaction is given by the equation: rate = k[A], where k is the rate constant and [A] is the concentration of reactant A.
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Integrated Rate Law

The integrated rate law for a first-order reaction relates the concentration of the reactant to time. It is expressed as ln[A] = -kt + ln[A]₀, where [A]₀ is the initial concentration, k is the rate constant, and t is time. When plotted, a graph of ln[A] versus time yields a straight line with a slope of -k, indicating that the reaction follows first-order kinetics.
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Graphing Reaction Kinetics

Graphing is a crucial tool in analyzing reaction kinetics. For first-order reactions, plotting the natural logarithm of the concentration of the reactant (ln[A]) against time results in a straight line. This linear relationship allows chemists to determine the rate constant (k) and understand the reaction's behavior over time, providing insights into the reaction mechanism and dynamics.
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Related Practice
Textbook Question

The following data were measured for the reaction 

(c) Calculate the rate constant with proper units?

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Textbook Question

Consider the gas-phase reaction between nitric oxide and bromine at 273 C: 2 NO1g2 + Br21g2¡2 NOBr1g2. The following data for the initial rate of appearance of NOBr were obtained: Experiment 3no4 1M 2 3br2 4 1M 2 Initial Rate 1M,s2 1 0.10 0.20 24 2 0.25 0.20 150 3 0.10 0.50 60 4 0.35 0.50 735 (b) Calculate the average value of the rate constant for the appearance of NOBr from the four data sets.

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Textbook Question

Consider the reaction of peroxydisulfate ion 1S2O82-2 with iodide ion 1I - 2 in aqueous solution: S2O8 2 - 1aq2 + 3 I - 1aq2¡2 SO42 - 1aq2 + I3- 1aq2 At a particular temperature, the initial rate of disappearance of S2O82 - varies with reactant concentrations in the following manner: Experiment 3S2o8 24 1M 2 3I4 1M 2 Initial Rate 1M,s2 1 0.018 0.036 2.6 * 10-6 2 0.027 0.036 3.9 * 10-6 3 0.036 0.054 7.8 * 10-6 4 0.050 0.072 1.4 * 10-5 (a) Determine the rate law for the reaction and state the units of the rate constant.

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Textbook Question

(a) The gas-phase decomposition of SO2Cl2, SO2Cl21g2 ¡SO21g2 + Cl21g2, is first order in SO2Cl2. At 600 K the half-life for this process is 2.3 * 105 s. What is the rate constant at this temperature?

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Textbook Question

As described in Exercise 14.41, the decomposition of sulfuryl chloride 1SO2Cl22 is a first-order process. The rate constant for the decomposition at 660 K is 4.5 * 10-2 s-1. (b) At what time will the partial pressure of SO2Cl2 decline to one-tenth its initial value?

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Textbook Question

The first-order rate constant for the decomposition of N2O5, 2 N2O51g2¡4 NO21g2 + O21g2, a t 70 C i s 6.82 * 10-3 s-1. Suppose we start with 0.0250 mol of N2O51g2 in a volume of 2.0 L. (a) How many moles of N2O5 will remain after 5.0 min?

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