Rank the following gases from least dense to most dense at 1.00 atm and 298 K: SO2,HBr,CO2.
(b) Calculate the molar mass of a gas if 2.50 g occupies 0.875 L at 685 torr and 35 °C
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Verified Solution
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Key Concepts
Ideal Gas Law
Molar Mass
Gas Laws and Conditions
Which of the following statements best explains why a closed balloon filled with helium gas rises in air? (a) Helium is a monatomic gas, whereas nearly all the molecules that make up air, such as nitrogen and oxygen, are diatomic. (b) The average speed of helium atoms is greater than the average speed of air molecules, and the greater speed of collisions with the balloon walls propels the balloon upward. (c) Because the helium atoms are of lower mass than the average air molecule, the helium gas is less dense than air. The mass of the balloon is thus less than the mass of the air displaced by its volume. (d) Because helium has a lower molar mass than the average air molecule, the helium atoms are in faster motion. This means that the temperature of the helium is greater than the air temperature. Hot gases tend to rise.
(a) Calculate the density of NO2 gas at 0.970 atm and 35 °C.
Calculate the molar mass of a vapor that has a density of 7.135 g/L at 12°C and 743 torr.
In the Dumas-bulb technique for determining the molar mass of an unknown liquid, you vaporize the sample of a liquid that boils below 100°C in a boiling-water bath and determine the mass of vapor required to fill the bulb. From the following data, calculate the molar mass of the unknown liquid: mass of unknown vapor, 1.012 g; volume of bulb, 354 cm3; pressure, 742 torr; temperature, 99°C.
The molar mass of a volatile substance was determined by the Dumas-bulb method described in Exercise 10.53. The unknown vapor had a mass of 0.846 g; the volume of the bulb was 354 cm3, pressure 752 torr, and temperature 100°C. Calculate the molar mass of the unknown vapor.