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Ch.9 - Molecular Geometry and Bonding Theories
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All textbooksBrown 14th EditionCh.9 - Molecular Geometry and Bonding TheoriesProblem 112a

Chapter 9, Problem 112a

The energy-level diagram in Figure 9.36 shows that the sideways overlap of a pair of p orbitals produces two molecular orbitals, one bonding and one antibonding. In ethylene there is a pair of electrons in the bonding π orbital between the two carbons. Absorption of a photon of the appropriate wavelength can result in promotion of one of the bonding electrons from the p2p to the p*2p molecular orbital. (a) Assuming this electronic transition corresponds to the HOMO-LUMO transition, what is the HOMO in ethylene?

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Once we have the overlap of 21 s. Atomic orbital and hydrogen. And this results in the formation of two molecular orbital one binding orbital which is sigma one S one anti bonding orbital which is sigma star one S. We have an electron getting excited from the bonding molecular orbital to the anti bonding molecular orbital. We're gonna assume that this transition is a home alarm. A transition were asked to identify the limo in hydrogen. We call that homo is the highest occupied or like your orbital and lou mo is the lowest unoccupied. I'm liking it. This is the electron is going from the bonding molecular orbital to the anti bonding molecular orbital. This means it's falling from sigma one S. To see my start. One S. This transition is gone from the humble state to the limo state. The limo Is Sigma Star one. S Thanks for watching my video and I hope it was helpful.
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a) Using only the valence atomic orbitals of a hydrogen atom and a fluorine atom, and following the model of Figure 9.46, how many MOs would you expect for the HF molecule?

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Textbook Question

Carbon monoxide, CO, is isoelectronic to N2. (d) Would you expect the p2p MOs of CO to have equal atomic orbital contributions from the C and O atoms? If not, which atom would have the greater contribution?

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Textbook Question

The energy-level diagram in Figure 9.36 shows that the sideways overlap of a pair of p orbitals produces two molecular orbitals, one bonding and one antibonding. In ethylene there is a pair of electrons in the bonding π orbital between the two carbons. Absorption of a photon of the appropriate wavelength can result in promotion of one of the bonding electrons from the p2p to the p*2p molecular orbital. (b) Assuming this electronic transition corresponds to the HOMO-LUMO transition, what is the LUMO in ethylene?

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Textbook Question

The energy-level diagram in Figure 9.36 shows that the sideways overlap of a pair of p orbitals produces two molecular orbitals, one bonding and one antibonding. In ethylene there is a pair of electrons in the bonding π orbital between the two carbons. Absorption of a photon of the appropriate wavelength can result in promotion of one of the bonding electrons from the p2p to the p*2p molecular orbital. (c) Is the C¬C bond in ethylene stronger or weaker in the excited state than in the ground state? Why?

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Textbook Question

Sulfur tetrafluoride 1SF42 reacts slowly with O2 to form sulfur tetrafluoride monoxide 1OSF42 according to the following unbalanced reaction: SF41g2 + O21g2¡OSF41g2 The O atom and the four F atoms in OSF4 are bonded to a central S atom. (a) Balance the equation.

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