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Ch.9 - Molecular Geometry and Bonding Theories
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All textbooksBrown 14th EditionCh.9 - Molecular Geometry and Bonding TheoriesProblem 112b

Chapter 9, Problem 112b

The energy-level diagram in Figure 9.36 shows that the sideways overlap of a pair of p orbitals produces two molecular orbitals, one bonding and one antibonding. In ethylene there is a pair of electrons in the bonding π orbital between the two carbons. Absorption of a photon of the appropriate wavelength can result in promotion of one of the bonding electrons from the p2p to the p*2p molecular orbital. (b) Assuming this electronic transition corresponds to the HOMO-LUMO transition, what is the LUMO in ethylene?

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Hi everyone. So you were at the overlap of 21 s orbital in hydrogen. And it's shown in the diagram below and it's going to result in the formation of two molecular orbital's one binding orbit which is signal one S one anti binding orbital which is sigma star one. S. An absorption of a high energy photon and exciting electron from the bonding molecular orbital to the anti bonding molecular orbital. We're gonna assume that the transition is home. A limo. Were asked to identify the homo in hydrogen we call that homo is the highest occupied molecular orbital. Um oh is the lowest unoccupied. I like it with This electron is born from the bonding molecular orbital. This is gonna be signal one s. And it's going to the anti bonding molecular orbital Which is single Star one. S. Let's go from sigma one. S. Two sigma star one. S. It says we're going to assume that this is a home alarm, a transition the electron is going to get promoted from homo to Lamo. Homo Is Sigma one. S Thanks for watching my video and I hope it will happen.
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Textbook Question
a) Using only the valence atomic orbitals of a hydrogen atom and a fluorine atom, and following the model of Figure 9.46, how many MOs would you expect for the HF molecule?

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Textbook Question

Carbon monoxide, CO, is isoelectronic to N2. (d) Would you expect the p2p MOs of CO to have equal atomic orbital contributions from the C and O atoms? If not, which atom would have the greater contribution?

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Textbook Question

The energy-level diagram in Figure 9.36 shows that the sideways overlap of a pair of p orbitals produces two molecular orbitals, one bonding and one antibonding. In ethylene there is a pair of electrons in the bonding π orbital between the two carbons. Absorption of a photon of the appropriate wavelength can result in promotion of one of the bonding electrons from the p2p to the p*2p molecular orbital. (a) Assuming this electronic transition corresponds to the HOMO-LUMO transition, what is the HOMO in ethylene?

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Textbook Question

The energy-level diagram in Figure 9.36 shows that the sideways overlap of a pair of p orbitals produces two molecular orbitals, one bonding and one antibonding. In ethylene there is a pair of electrons in the bonding π orbital between the two carbons. Absorption of a photon of the appropriate wavelength can result in promotion of one of the bonding electrons from the p2p to the p*2p molecular orbital. (c) Is the C¬C bond in ethylene stronger or weaker in the excited state than in the ground state? Why?

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Textbook Question

Sulfur tetrafluoride 1SF42 reacts slowly with O2 to form sulfur tetrafluoride monoxide 1OSF42 according to the following unbalanced reaction: SF41g2 + O21g2¡OSF41g2 The O atom and the four F atoms in OSF4 are bonded to a central S atom. (a) Balance the equation.

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Textbook Question

Sulfur tetrafluoride (SF4) reacts slowly with O2 to form sulfur tetrafluoride monoxide (OSF4) according to the following unbalanced reaction: SF4(g) + O2(g) → OSF4(g) The O atom and the four F atoms in OSF4 are bonded to a central S atom. (b) Write a Lewis structure of OSF4 in which the formal charges of all atoms are zero.

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