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Ch.9 - Molecular Geometry and Bonding Theories
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All textbooksBrown 14th EditionCh.9 - Molecular Geometry and Bonding TheoriesProblem 7b

Chapter 9, Problem 7b

In the hydrocarbon (b) How many s bonds are there in the molecule?

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Hey everyone! So here it says, the structure of pathetic acid is shown below the term of the number of pI bonds present, empathetic acid. So remember A single bond is composed of σ bond. A double bond is composed of one sigma And one pi bond. Right, so either one of these could be your pi bond. And then a triple bond is composed of one sigma And two Pi bonds. So if we take a look here, we have a lot of single and double bonds present. So here we have one, two, three, four, five, five double bonds involved. So that's five pi bonds. Okay, so pathologist acid has within it five pi bonds.
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Textbook Question

The orbital diagram that follows presents the final step in the formation of hybrid orbitals by a silicon atom. (a) Which of the following best describes what took place before the step pictured in the diagram: (i) Two 3p electrons became unpaired, (ii) An electron was promoted from the 2p orbital to the 3s orbital, or (iii) An electron was promoted from the 3s orbital to the 3p orbital?

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Textbook Question

The orbital diagram that follows presents the final step in the formation of hybrid orbitals by a silicon atom. (b) What type of hybrid orbital is produced in this hybridization?

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Textbook Question

In the hydrocarbon

(a) What is the hybridization at each carbon atom in the molecule?

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Textbook Question

In the hydrocarbon

(d) Identify all the 120° bond angles in the molecule.

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Textbook Question

The drawing below shows the overlap of two hybrid orbitals to form a bond in a hydrocarbon. (a) Which of the following types of bonds is being formed: (i) C¬C s, (ii) C¬C p, or (iii) C¬H s?

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Textbook Question

The drawing below shows the overlap of two hybrid orbitals to form a bond in a hydrocarbon. (b) Which of the following could be the identity of the hydrocarbon: (i) CH4, (ii) C2H6, (iii) C2H4, or (iv) C2H2?

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