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Ch.9 - Molecular Geometry and Bonding Theories

Chapter 9, Problem 60a

Benzaldehyde, C7H6O, is a fragrant substance responsible for the aroma of almonds. Its Lewis structure is

(a) What is the hybridization at each of the carbon atoms of the molecule?

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Welcome back everyone. The lewis structure of acetic acid. A byproduct of fermentation is illustrated in the following figure, determine the hybridization of each carbon atom in the molecule. So let's begin by numbering our carbons. We have the left most carbon as carbon one and the right most carbon as carbon number two. Recall that our number of electron domains on an atom will correspond to the hybridization And so beginning with carbon # one. So at carbon number one, we can count three single carbon hydrogen bonds and one single carbon carbon bond, meaning we would have at carbon number one, a total of four domains Electron domains. And this is attributed from our four sigma bonds on carbon number one. So therefore this corresponds to sp three hybridization when we have four domains. So now moving to carbon number two. So at carbon number two, we can see that we have a carbon oxygen double bond, a carbon carbon single bond and a carbon oxygen single bond. So at carbon # two We have a total Of three domains, 3 electron domains. We have to sigma bonds and one pi bond being our carbon oxygen double bond. And so therefore because we have three domains, that means that we have Sp two hybridization for that carbon. And so for our final answers, we can highlight for carbon number one, sorry, that's carbon number one. Here we highlight its sp three hybridization and carbon number two. It's sp two hybridization and this will correspond to choice be in the multiple choice as the correct answer. So I hope that this made sense. And let us know if you have any questions.