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Ch.7 - Periodic Properties of the Elements

Chapter 7, Problem 112

Mercury in the environment can exist in oxidation states 0, +1, and +2. One major question in environmental chemistry research is how to best measure the oxidation state of mercury in natural systems; this is made more complicated by the fact that mercury can be reduced or oxidized on surfaces differently than it would be if it were free in solution. XPS, X-ray photoelectron spectroscopy, is a technique related to PES (see Exercise 7.111), but instead of using ultraviolet light to eject valence electrons, X rays are used to eject core electrons. The energies of the core electrons are different for different oxidation states of the element. In one set of experiments, researchers examined mercury contamination of minerals in water. They measured the XPS signals that corresponded to electrons ejected from mercury's 4f orbitals at 105 eV, from an X-ray source that provided 1253.6 eV of energy 11 ev = 1.602 * 10-19J2. The oxygen on the mineral surface gave emitted electron energies at 531 eV, corresponding to the 1s orbital of oxygen. Overall the researchers concluded that oxidation states were +2 for Hg and -2 for O. (b) Compare the energies of the 4f electrons in mercury and the 1s electrons in oxygen from these data to the first ionization energies of mercury and oxygen from the data in this chapter.

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hey everyone in this example we need to calculate the experimental ionization energy and units of joules per mole for 10. And strontium. If their experimental charges are 7.35 electron volts and 5.69 electron volts. So beginning with our calculation of ionization energy for 10, We would recall that that we would begin this by taking its charge given in the prompt as 7.35 electro volts. We're going to recall the charge of an electron which is 1.602 times 10 to the negative 19th power jules per electra vault. Which will allow us to cancel our units of electron volts. But because we want our final units to be killed jules Permal we would multiply by the conversion factor where we would recall that for one jewel we have our prefix kilo which means 10 to the negative third power kilo jewels. So now we're able to cancel our units of jewels. And now we want to apply by our last or multiplied by our last conversion factor. Where we would recall avocados number which tells us that we would have 6.022 times 10 to the 23rd power atoms per more. So what we're left with is units of kilograms times Adams Permal. Which we can interpret as kilo, joules per mole because our final answer here is going to equal a value of kayla jules Permal of An Atom of 10. So moving on to the ionization energy calculation for strontium, we're going to follow the same process where we're going to take the charge or the experimental charge given in the prompt for strontium as 5.69 electro volts. We're going to recall that our charge of an electron is 1.6 so two times to the negative 19th power jewels per electoral vote. So now we're able to cancel out our units of electron volts. And next we're going to again convert from jules, tequila jewels by recalling our prefix kilo tells us for one kg jule we have 10 to the negative third power kilo jewels. Next we're going to multiply by because we would be able to cancel our jewels. So we want to get two kg per mole by recalling avocados number which tells us we have six point oh 22 times 10 to the 23rd power atoms Permal. And so now what we're going to get here is a value equal to 549 kg jewels Permal as our ionization energy for strontium for an atom of strontium. And so for our final answers, we have these two values that were boxing in here to complete this example. So I hope that everything I explained was clear. If you have any questions, please leave them down below. Otherwise I'll see everyone in the next practice video
Related Practice
Textbook Question

Moseley established the concept of atomic number by studying X rays emitted by the elements. The X rays emitted by some of the elements have the following wavelengths: Element Wavelength (pm) Ne 1461 Ca 335.8 Zn 143.5 Zr 78.6 Sn 49.1 (e) A particular element emits X rays with a wavelength of 98.0 pm. What element do you think it is?

Textbook Question

One way to measure ionization energies is ultraviolet photoelectron spectroscopy (PES), a technique based on the photoelectric effect. (Section 6.2) In PES, monochromatic light is directed onto a sample, causing electrons to be emitted. The kinetic energy of the emitted electrons is measured. The difference between the energy of the photons and the kinetic energy of the electrons corresponds to the energy needed to remove the electrons (that is, the ionization energy). Suppose that a PES experiment is performed in which mercury vapor is irradiated with ultraviolet light of wavelength 58.4 nm. (c) The kinetic energy of the emitted electrons is measured to be 1.72 * 10-18 J. What is the first ionization energy of Hg, in kJ>mol?

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Textbook Question

One way to measure ionization energies is ultraviolet photoelectron spectroscopy (PES), a technique based on the photoelectric effect. (Section 6.2) In PES, monochromatic light is directed onto a sample, causing electrons to be emitted. The kinetic energy of the emitted electrons is measured. The difference between the energy of the photons and the kinetic energy of the electrons corresponds to the energy needed to remove the electrons (that is, the ionization energy). Suppose that a PES experiment is performed in which mercury vapor is irradiated with ultraviolet light of wavelength 58.4 nm. (d) Using Figure 7.10, determine which of the halogen elements has a first ionization energy closest to that of mercury.

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Textbook Question

When magnesium metal is burned in air (Figure 3.6), two products are produced. One is magnesium oxide, MgO. The other is the product of the reaction of Mg with molecular nitrogen, magnesium nitride. When water is added to magnesium nitride, it reacts to form magnesium oxide and ammonia gas. (c) In an experiment, a piece of magnesium ribbon is burned in air in a crucible. The mass of the mixture of MgO and magnesium nitride after burning is 0.470 g. Water is added to the crucible, further reaction occurs, and the crucible is heated to dryness until the final product is 0.486 g of MgO. What was the mass percentage of magnesium nitride in the mixture obtained after the initial burning?

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Textbook Question

When magnesium metal is burned in air (Figure 3.6), two products are produced. One is magnesium oxide, MgO. The other is the product of the reaction of Mg with molecular nitrogen, magnesium nitride. When water is added to magnesium nitride, it reacts to form magnesium oxide and ammonia gas. (d) Magnesium nitride can also be formed by reaction of the metal with ammonia at high temperature. Write a balanced equation for this reaction. If a 6.3-g Mg ribbon reacts with 2.57 g NH31g2 and the reaction goes to completion, which component is the limiting reactant? What mass of H21g2 is formed in the reaction?

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Textbook Question

Potassium superoxide, KO2, is often used in oxygen masks (such as those used by firefighters) because KO2 reacts with CO2 to release molecular oxygen. Experiments indicate that 2 mol of KO2(s) react with each mole of CO2(g). (c) What mass of KO2(s) is needed to consume 18.0 g CO2(g)? What mass of O2(g) is produced during this reaction?

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