Scientists have speculated that element 126 might have a moderate stability, allowing it to be synthesized and characterized. Predict what the condensed electron configuration of this element might be.

Video transcript

Hello everyone in this video. We're making a possible election configuration up for the element of atomic number 137. So if we're trying to look for the element with atomic number 137, you won't be able to find it because it's not on a pr table. There's something that the problem has made up for us. As you can see from pure a table, the element with the highest atomic number is going to be this guy right here. That's the atomic number of 1:18. So how do we find an electron configuration for something that's not even there? Well, we kind of have to use our imagination. So, a condensed electric configuration is seen as a noble gas configuration. If your call this column here is going to be all of our noble guesses. And since this guy right here has the highest number of or the atomic number, the high atomic number they were going to go ahead and use this one because this would be the last noble gas that we are aware of. So starting off our noble gas configuration or condensed electron configuration, we'll put in brackets O. G. All right. So as you recall from general chemistry one that the atomic number is also equal to how many protons and electrons that the element or atom contains. So if we have known this and we know this subtract that. So we know how many more electrons we need to consider for our electronic configuration. So 137, which is what the problem wants us to find. And the noon Atomic number of 1: from this Nobel gas here, It's going to equal to 19 and that's how many electrons we need to consider. So if we were to actually do or let's say that The element with atomic # 1, 37 Israel. But go ahead and continue down the table to get our electric configuration. Right. So if you take a look here, the next orbital is that we need to consider? He's gonna go from S two F two p orbital's And like I said, we need 19 total electrons. So let's break it apart a little bit. R s orbital, we know can contain only two electrons. The F orbital can contain a total of 14 electrons So far, that's equal to 16 electrons. And moving on to the people That can hold a total of six electrons, but we don't need all six. We need how many more? Let's see, 19-16. That's three. So we only need three electrons from this p orbital here. So three electrons. So, with this in mind and the role numbers in mind, let's go ahead actually label those 1234567. If this table were to be extended, we'll have 89, 10 and so on row, but we'll just kind of have to imagine that in your head. So continuing on, we can see here that we're dealing with the S So we'll have R eight S two now for F, That would be six f 14. So we have two electrons and 14 electrons from the S&F so two and 14 to get 16. Now, we need three electrons left for the P orbital to complete our 19 missing electrons. So that's going to be dates P three. So we use the O. G element as our noble guests. They continued on to do our electric configuration with a possible roll number. And this is going to be the possible condensed electronic configuration of an element for atomic number of 1:37. Thank you.