Skip to main content
Ch.6 - Electronic Structure of Atoms

Chapter 6, Problem 68a

(a) The average distance from the nucleus of a 3s electron in a chlorine atom is smaller than that for a 3p electron. In light of this fact, which orbital is higher in energy?

Verified Solution
Video duration:
51s
This video solution was recommended by our tutors as helpful for the problem above.
1123
views
Was this helpful?

Video transcript

Hello everyone in this video being asked if a four p electron has a higher energy than four S electron And were given the background information that a four p electron is further from the nucleus than a four s electron. So the electron, with the greater average distance from the nucleus has a smaller attraction for the nucleus and therefore higher in energy. We're comparing here, The four p electron versus a four S electron. So with that being said, then a four P electron will definitely have a higher energy than a four S electron. And this is going to be our final answer for this question.