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Ch.5 - Thermochemistry
Chapter 5, Problem 36

Suppose that the gas-phase reaction 2 NO(g) + O2(g) → 2 NO2(g) were carried out in a constant-volume container at constant temperature. (a) Would the measured heat change represent _x001F_H or _x001F_E? (b) If there is a difference, which quantity is larger for this reaction? (c) Explain your answer to part (b).

Verified step by step guidance
1
Step 1: Understand the difference between enthalpy change (ΔH) and internal energy change (ΔE). ΔH is the heat change at constant pressure, while ΔE is the heat change at constant volume.
Step 2: Recognize that the problem states the reaction occurs in a constant-volume container, which means the measured heat change represents ΔE, the change in internal energy.
Step 3: Recall the relationship between ΔH and ΔE: ΔH = ΔE + ΔnRT, where Δn is the change in moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.
Step 4: Calculate Δn for the reaction: 2 NO(g) + O2(g) → 2 NO2(g). The change in moles of gas, Δn, is (moles of products) - (moles of reactants) = 2 - (2 + 1) = -1.
Step 5: Since Δn is negative, ΔH = ΔE + ΔnRT will be less than ΔE, meaning ΔE is larger than ΔH for this reaction.