Skip to main content
Ch.5 - Thermochemistry
Chapter 5, Problem 35

Assume that 2 moles of water are formed according to the following reaction at constant pressure (101.3 kPa) and constant temperature (298 K): 2 H2(g) + O2(g) → 2 H2O(l). (b) Calculate _x001F_E for the reaction using your answer to (a).

Verified step by step guidance
1
Step 1: Understand the reaction and the concept of enthalpy change (ΔE). The reaction given is 2 H2(g) + O2(g) → 2 H2O(l). The enthalpy change for a reaction at constant pressure is related to the heat absorbed or released.
Step 2: Use the standard enthalpy of formation values to calculate the enthalpy change for the reaction. The standard enthalpy of formation (ΔH_f^°) is the change in enthalpy when one mole of a compound is formed from its elements in their standard states.
Step 3: Write the expression for the enthalpy change of the reaction (ΔH_rxn) using the standard enthalpies of formation: ΔH_rxn = [2 * ΔH_f^°(H2O(l))] - [2 * ΔH_f^°(H2(g)) + ΔH_f^°(O2(g))].
Step 4: Recognize that the standard enthalpy of formation for elements in their standard state, such as H2(g) and O2(g), is zero. Therefore, the expression simplifies to ΔH_rxn = 2 * ΔH_f^°(H2O(l)).
Step 5: Use the known value of ΔH_f^°(H2O(l)) from a data table to calculate ΔH_rxn. This will give you the enthalpy change for the formation of 2 moles of water under the given conditions.
Related Practice