Skip to main content
Ch.5 - Thermochemistry
Chapter 5, Problem 119a

Suppose an Olympic diver who weighs 52.0 kg executes a straight dive from a 10-m platform. At the apex of the dive, the diver is 10.8 m above the surface of the water. (a) What is the potential energy of the diver at the apex of the dive, relative to the surface of the water?

Verified step by step guidance
1
Identify the formula for gravitational potential energy: $PE = mgh$, where $m$ is mass, $g$ is the acceleration due to gravity, and $h$ is the height above the reference point.
Determine the mass $m$ of the diver, which is given as 52.0 kg.
Use the standard acceleration due to gravity $g = 9.8 \text{ m/s}^2$.
Identify the height $h$ of the diver above the surface of the water, which is 10.8 m.
Substitute the values of $m$, $g$, and $h$ into the potential energy formula to find the potential energy at the apex of the dive.

Verified Solution

Video duration:
1m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Potential Energy

Potential energy is the energy stored in an object due to its position in a gravitational field. It is calculated using the formula PE = mgh, where PE is potential energy, m is mass, g is the acceleration due to gravity (approximately 9.81 m/s²), and h is the height above a reference point, typically the ground or water surface.
Recommended video:
Guided course
00:34
Kinetic & Potential Energy

Mass

Mass is a measure of the amount of matter in an object, typically expressed in kilograms (kg). In this context, the mass of the diver is crucial for calculating potential energy, as it directly influences the energy stored due to the diver's height above the water.
Recommended video:

Height in Gravitational Potential Energy

Height is a critical factor in determining gravitational potential energy. The greater the height of an object above a reference point, the more potential energy it possesses. In this scenario, the height of the diver above the water surface is essential for calculating the potential energy at the apex of the dive.
Recommended video:
Guided course
00:34
Kinetic & Potential Energy
Related Practice
Textbook Question

Sucrose (C12H22O11) is produced by plants as follows: 12 CO2(g) + 11 H2O(l) → C12H22O11 + 12 O2(g) H = 5645 kJ About 4.8 g of sucrose is produced per day per square meter of the earth's surface. The energy for this endothermic reaction is supplied by the sunlight. About 0.1 % of the sunlight that reaches the earth is used to produce sucrose. Calculate the total energy the sun supplies for each square meter of surface area. Give your answer in kilowatts per square meter 1kW/m2 where 1W = 1 J/s2.

833
views
Open Question
It is estimated that the net amount of carbon dioxide fixed by photosynthesis on the landmass of Earth is 5.5 * 10^16 g/yr of CO2. Assume that all this carbon is converted into glucose. (b) Calculate the average rate of conversion of solar energy into plant energy in megawatts, MW (1 W = 1 J/s). A large nuclear power plant produces about 10^3 MW. The energy of how many such nuclear power plants is equivalent to the solar energy conversion?
Textbook Question

At 20 °C (approximately room temperature) the average velocity of N2 molecules in air is 1050 mph. (b) What is the kinetic energy (in J) of an N2 molecule moving at this speed?

1356
views
1
comments
Textbook Question

Suppose an Olympic diver who weighs 52.0 kg executes a straight dive from a 10-m platform. At the apex of the dive, the diver is 10.8 m above the surface of the water. (b) Assuming that all the potential energy of the diver is converted into kinetic energy at the surface of the water, at what speed, in m>s, will the diver enter the water?

591
views
Textbook Question

Consider the following unbalanced oxidation-reduction reactions in aqueous solution:

Ag+(aq) + Li(s) → Ag(s) + Li+(aq)

Fe(s) + Na+(aq) → Fe2+(aq) + Na(s)

K(s) + H2O(l) → KOH(aq) + H2(g)

(a) Balance second reaction.

681
views
Textbook Question

Consider the following unbalanced oxidation-reduction reactions in aqueous solution:

Ag+(aq) + Li(s) → Ag(s) + Li+(aq)

Fe(s) + Na+(aq) → Fe2+(aq) + Na(s)

K(s) + H2O(l) → KOH(aq) + H2(g)

(a) Balance third reaction.

609
views