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Ch.5 - Thermochemistry
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All textbooksBrown 14th EditionCh.5 - ThermochemistryProblem 49b

Chapter 5, Problem 49b

(b) The specific heat of aluminum is 0.9 J/(g - K). Calculate its molar heat capacity.

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Hey everyone, we're asked to calculate the molar heat capacity of manganese, given its specific heat of 0.4 80 jewels over grams times kelvin. To answer this question, all we need to do is use our dimensional analysis starting off with 0.480 jewels over grams times kelvin using manganese molar mass, which is 54.94 g Of Manganese per one mole of Manganese. We end up with a molar heat capacity of 26. jewels over Mole Times Kelvin, which is going to be our final answer. Now, I hope that made sense and let us know if you have any questions.
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Consider the decomposition of liquid benzene, C6H6(l), to gaseous acetylene, C2H2(g): C6H6(l) → 3 C2H2(g) ΔH = +630 kJ (b) What is H for the formation of 1 mol of acetylene?

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Consider the decomposition of liquid benzene, C6H6(l), to gaseous acetylene, C2H2(g): C6H6(l) → 3 C2H2(g) ΔH = +630 kJ (d) If C6H6(g) were consumed instead of C6H6(l), would you expect the magnitude of ΔH to increase, decrease, or stay the same? Explain.

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