Pure acetic acid, known as glacial acetic acid, is a liquid with a density of 1.049 g/mL at 25 C. Calculate the molarity of a solution of acetic acid made by dissolving 20.00 mL of glacial acetic acid at 25 C in enough water to make 250.0 mL of solution.

Video transcript

And everyone to ask that the modularity of the solution made by Diluting 15 ml. A pure sulfuric acid with a density of 1.8302 g per centimeter cube 2 500 ml. We call that clarity. It was the malls of the salute lot about leaders. The solution. Let me know that one same meter cubed Was one male leader. We need to find the moles of sulfuric acid. We need to first use the density of sulfuric acid to find the mass. We have 1.83 02 g per one million. We're diluting 15 ml And this gives us 27.45 grams. Now you can use the molar mass to find the moles of sulfuric acid, 27.45 g of sulfuric acid And in one mold. Oh sulfuric acid. Have the molar mass which is to has 1.008g 32.066 g plus four times 15 .999 g. We get 98.08 g. Let's give us 0.28 smalls of sulfuric acid. So now we need to convert our volume of solution into leaders mL. We have 1000 ml in one liter. Just give us 0.5 L. Then I would use the moles of sulfuric acid in the volume of the solution. To find the polarity 0.28 malls Is 0.5 L. Thanks giving us 0.56 Baller. Thanks for watching my video. And I hope it was up for