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Ch.3 - Chemical Reactions and Reaction Stoichiometry
Chapter 3, Problem 80a

One of the steps in the commercial process for converting ammonia to nitric acid is the conversion of NH3 to NO: 4 NH31g2 + 5 O21g2¡4 NO1g2 + 6 H2O1g2 In a certain experiment, 2.00 g of NH3 reacts with 2.50 g of O2. (a) Which is the limiting reactant?

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Step 1: Write down the balanced chemical equation. In this case, it is already given: 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g)
Step 2: Calculate the number of moles of each reactant. The molar mass of NH3 is approximately 17 g/mol and the molar mass of O2 is approximately 32 g/mol. So, divide the given mass of each reactant by its molar mass to find the number of moles.
Step 3: Determine the stoichiometric ratio from the balanced chemical equation. In this case, it is 4 moles of NH3 to 5 moles of O2.
Step 4: Compare the ratio of the number of moles of each reactant to the stoichiometric ratio. The reactant that is less than or equal to its stoichiometric ratio is the limiting reactant.
Step 5: If it's not clear which reactant is the limiting one, calculate the amount of product that each reactant could produce. The reactant that produces the least amount of product is the limiting reactant.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Stoichiometry

Stoichiometry is the calculation of reactants and products in chemical reactions based on the balanced chemical equation. It allows chemists to determine the proportions of substances involved in a reaction, which is essential for identifying limiting reactants. In this case, stoichiometry will help calculate how much NH3 and O2 are needed to produce NO and H2O.
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Limiting Reactant

The limiting reactant is the substance that is completely consumed first in a chemical reaction, thus determining the maximum amount of product that can be formed. Identifying the limiting reactant is crucial for predicting the yield of products. In this experiment, comparing the mole ratios of NH3 and O2 will reveal which reactant limits the formation of NO.
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Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). It is essential for converting between grams and moles, which is necessary for stoichiometric calculations. In this question, calculating the molar masses of NH3 and O2 will allow for the determination of the number of moles present, facilitating the identification of the limiting reactant.
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Related Practice
Textbook Question

Aluminum hydroxide reacts with sulfuric acid as follows: 2 Al1OH231s2 + 3 H2SO41aq2¡Al21SO4231aq2 + 6 H2O1l2 How many moles of Al21SO423 can form under these conditions?

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Textbook Question

Aluminum hydroxide reacts with sulfuric acid as follows: 2 Al1OH231s2 + 3 H2SO41aq2¡Al21SO4231aq2 + 6 H2O1l2 How many moles of the excess reactant remain after the completion of the reaction?

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Textbook Question

The fizz produced when an Alka-Seltzer tablet is dissolved in water is due to the reaction between sodium bicarbonate 1NaHCO32 and citric acid 1H3C6H5O72: 3 NaHCO31aq2 + H3C6H5O71aq2¡ 3 CO21g2 + 3H2O1l2 + Na3C6H5O71aq2 In a certain experiment 1.00 g of sodium bicarbonate and 1.00 g of citric acid are allowed to react. (a) Which is the limiting reactant? (b) How many grams of carbon dioxide form? (c) How many grams of the excess reactant remain after the limiting reactant is completely consumed?

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Textbook Question

One of the steps in the commercial process for converting ammonia to nitric acid is the conversion of NH3 to NO: 4 NH31g2 + 5 O21g2¡4 NO1g2 + 6 H2O1g2 In a certain experiment, 2.00 g of NH3 reacts with 2.50 g of O2. (c) How many grams of the excess reactant remain after the limiting reactant is completely consumed?

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Textbook Question

One of the steps in the commercial process for converting ammonia to nitric acid is the conversion of NH3 to NO: 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g) In a certain experiment, 2.00 g of NH3 reacts with 2.50 g of O2. (d) Show that your calculations in parts (b) and (c) are consistent with the law of conservation of mass.

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Textbook Question

Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A solution containing 3.50 g of sodium carbonate is mixed with one containing 5.00 g of silver nitrate. How many grams of sodium carbonate are present after the reaction is complete? How many grams of sodium nitrate are present after the reaction is complete?

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