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Ch.3 - Chemical Reactions and Reaction Stoichiometry
Chapter 3, Problem 78b

Aluminum hydroxide reacts with sulfuric acid as follows: 2 Al1OH231s2 + 3 H2SO41aq2¡Al21SO4231aq2 + 6 H2O1l2 How many moles of Al21SO423 can form under these conditions?

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Step 1: Identify the balanced chemical equation. In this case, it is: 2 Al(OH)3 (s) + 3 H2SO4 (aq) → 2 Al(SO4)3 (aq) + 6 H2O (l)
Step 2: Identify the limiting reactant. The limiting reactant is the reactant that is completely consumed in the reaction and determines the maximum amount of product that can be formed. In this problem, we are not given the amounts of the reactants, so we cannot determine the limiting reactant.
Step 3: Use the stoichiometry of the reaction to determine the amount of Al(SO4)3 that can be formed. According to the balanced chemical equation, 2 moles of Al(OH)3 react with 3 moles of H2SO4 to form 2 moles of Al(SO4)3. Therefore, the ratio of Al(OH)3 to Al(SO4)3 is 1:1.
Step 4: If the amount of Al(OH)3 is known, multiply it by the stoichiometric ratio to find the amount of Al(SO4)3 that can be formed. If the amount of H2SO4 is known, divide it by the stoichiometric ratio to find the amount of Al(SO4)3 that can be formed.
Step 5: The answer to the problem is the amount of Al(SO4)3 that can be formed, which is determined by the amount of the limiting reactant and the stoichiometry of the reaction.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Stoichiometry

Stoichiometry is the branch of chemistry that deals with the quantitative relationships between the reactants and products in a chemical reaction. It allows us to calculate the amount of substances consumed and produced in a reaction based on balanced chemical equations. Understanding stoichiometry is essential for determining how many moles of a product can be formed from given amounts of reactants.
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Balanced Chemical Equation

A balanced chemical equation represents a chemical reaction where the number of atoms for each element is the same on both sides of the equation. This balance ensures the law of conservation of mass is upheld. In the provided reaction, the coefficients indicate the molar ratios of reactants and products, which are crucial for stoichiometric calculations.
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Mole Concept

The mole concept is a fundamental principle in chemistry that defines the amount of substance. One mole corresponds to 6.022 x 10²³ entities (atoms, molecules, etc.). This concept is vital for converting between grams and moles, allowing chemists to quantify reactants and products in a reaction, facilitating calculations like those needed to determine the moles of aluminum sulfate produced.
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Related Practice
Textbook Question

Sodium hydroxide reacts with carbon dioxide as follows: 2 NaOH(s) + CO2(g) → Na2CO3(s) + H2O(l) How many moles of Na2CO3 can be produced?

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Textbook Question

Sodium hydroxide reacts with carbon dioxide as follows: 2 NaOH1s2 + CO21g2¡Na2CO31s2 + H2O1l2 How many moles of the excess reactant remain after the completion of the reaction?

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Textbook Question

Aluminum hydroxide reacts with sulfuric acid as follows: 2 Al1OH231s2 + 3 H2SO41aq2¡Al21SO4231aq2 + 6 H2O1l2 Which is the limiting reactant when 0.500 mol Al1OH23 and 0.500 mol H2SO4 are allowed to react?

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Textbook Question

Aluminum hydroxide reacts with sulfuric acid as follows: 2 Al1OH231s2 + 3 H2SO41aq2¡Al21SO4231aq2 + 6 H2O1l2 How many moles of the excess reactant remain after the completion of the reaction?

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Textbook Question

The fizz produced when an Alka-Seltzer tablet is dissolved in water is due to the reaction between sodium bicarbonate 1NaHCO32 and citric acid 1H3C6H5O72: 3 NaHCO31aq2 + H3C6H5O71aq2¡ 3 CO21g2 + 3H2O1l2 + Na3C6H5O71aq2 In a certain experiment 1.00 g of sodium bicarbonate and 1.00 g of citric acid are allowed to react. (a) Which is the limiting reactant? (b) How many grams of carbon dioxide form? (c) How many grams of the excess reactant remain after the limiting reactant is completely consumed?

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Textbook Question

One of the steps in the commercial process for converting ammonia to nitric acid is the conversion of NH3 to NO: 4 NH31g2 + 5 O21g2¡4 NO1g2 + 6 H2O1g2 In a certain experiment, 2.00 g of NH3 reacts with 2.50 g of O2. (a) Which is the limiting reactant?

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