Tests on human subjects in Boston in 1965 and 1966, following the era of atomic bomb testing, revealed average quantities of about 2 pCi of plutonium radioactivity in the average person. How many disintegrations per second does this level of activity imply? If each alpha particle deposits 8 * 10^-13 J of energy and if the average person weighs 75 kg, calculate the number of rads and rems of radiation in 1 yr from such a level of plutonium.
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Step 1: Convert the radioactivity from picocuries (pCi) to disintegrations per second (dps). Use the conversion factor: 1 Curie (Ci) = 3.7 x 10^10 disintegrations per second. Since 1 pCi = 10^-12 Ci, calculate the disintegrations per second for 2 pCi.
Step 2: Calculate the total energy deposited in 1 year. First, find the number of disintegrations in 1 year by multiplying the disintegrations per second by the number of seconds in a year (365 days x 24 hours/day x 3600 seconds/hour). Then, multiply the total number of disintegrations by the energy deposited per alpha particle (8 x 10^-13 J).
Step 3: Calculate the absorbed dose in rads. The absorbed dose in rads is the energy deposited per unit mass of tissue. Use the formula: absorbed dose (rads) = (total energy deposited in joules) / (mass in kg x 0.01 J/kg).
Step 4: Convert the absorbed dose from rads to rems. Since the radiation weighting factor for alpha particles is 20, use the formula: dose in rems = dose in rads x radiation weighting factor.
Step 5: Summarize the calculations to find the number of disintegrations per second, the total energy deposited in 1 year, the absorbed dose in rads, and the dose in rems.