Complete and balance the following nuclear equations by supplying the missing particle: (d) 5826Fe + 2 10n¡6027Co + ?

Video transcript

Welcome back everyone in this example. We need to identify the missing new Clyde and then complete and balanced the nuclear equation. So we're given the nuclear equation where we have 192 raid on with its atomic number 76 reacting with three moles of our beta particle, the neutron corresponding to an atomic number of zero and mass number of one. Whereas a product we have 195 Act any um produced with its atomic number 78. And we need to identify the unknown product new glide, which we will represent by the chemical symbol X. With its unknown atomic number A. And it's unknown mass number Z. So Z is our and sorry, we have that backwards. Our atomic number is going to be Z. And our mass number is going to be represented by the symbol A. So let's notify that down. We have this is our mass number and see is our atomic number. So we're going to use our knowns in our equation to solve for our unknowns A. And Z. Where Z is going to ultimately tell us the identity of our unknown new Clyde and ultimately allow us to have a complete balanced nuclear equation once we know it's full identity. So let's begin by solving for its mass number. We're going to plug in our knowns. We know from our equation that we have the mass number of Reagan being 1 92 added to the three moles of our mass number of our neutron being one. So we would multiply these two values. And on our product side we're setting this equal to our mass number of act any um being 1 95 added to our unknown mass number A which is what we need to solve for simplifying this. We will have 195 equal to plus a meaning that are unknown Mass number is going to equal a value of zero. So solving for now our atomic number z plugging in our knowns from our equation are atomic number for radon is given us 76 in the prompt. We're adding this to our second reactant where we have three moles of our atomic number of our nucleus. Or sorry, neutron beta particle being zero. This is then set equal to our product side where we have the atomic number of Act any um being 78 added to our unknown atomic number which we're solving for Z. So simplifying this, we would have 76 rather 70. Yes, 76 because three times zero is zero Equal to 78 plus Z plus Z. Here. Where we would have Z equal to the value negative two. When we take 76 78 from 76. And so looking at our two values here, we would recognize that since we have the atomic number of negative two, we're going to have to recall based on our particles that we learned in class that a atomic number of negative one and a mass number of zero. And let's use red for mass number again corresponds to a particle being a beta particle, which we recall is represented by the symbol E for an electron. And so this is likely undergoing two beta emissions, which is why we have an atomic number of negative two. So we likely will just multiply this by two. Where we would have for our full nuclear equation 92. rate on With the atomic number 76. And sorry, this is a nine here reacting with three moles of our beta particle being our neutron. In this case where we have the mass number one and atomic number zero, we're on our product side. We have 1 95 act any um as a product with the atomic number 78 our product new glide being our to beta emissions of our beta particle corresponding to atomic number negative one and mass number zero. So this is again our beta particle. And so our final answers are going to be our missing new Clyde which we determined is our beta particle and our bounced nuclear equation which is boxed here below. So everything boxed in and highlighted in yellow represents our two final answers. I hope everything I explained was clear. If you have any questions, leave them down below and I will see everyone in the next practice video