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Ch.20 - Electrochemistry

Chapter 20, Problem 46d

Is each of the following substances likely to serve as an oxidant or a reductant: (d) N2O51g2?

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Hey everyone today, we're being asked to use the standard reduction potential of Chrome 8 to determine if it is an oxidizing or reducing agent. Now to do this, we need to actually utilize the reduction half reaction of Chrome eight. Now, this is an experimental value that we can find in our textbooks. But in general, the actual half reaction would look something like this. We would have chromite in an aqueous solution which reacts for water molecules and three electrons will be on our react inside to form chromium three hydroxide, C R O H three, Oh sorry, OH three, which is solid And five hydroxy sites. Aquarius And the total reaction will have a reduction potential. A standard reduction potential of negative 0.13V. Now this is because we're dealing with a reduction half reaction, it is gaining electrons which means that the reduction potential would be negative. And we've also answered our question, the reaction or the reduction half reaction occurs with chromium reacting with three electrons. It is gaining three electrons, which means it is being reduced and is therefore the oxidizing agent as it helps oxidize the water. Another way that we can think about it, if you want a simpler way to do it is that if when you read out the half reaction, if the the substance in question is on the left on the reactant side, it will be the oxidizing agent. If it is on the product side it will be the reducing agent. But Chromium gains three electrons. It gets reduced and is therefore the oxidizing agent dicing agent, I hope this helps, and I look forward to seeing you in the next one.